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rodikova [14]
2 years ago
12

When a number x is added to it's square, the total is 12. find two possible values of x​

Mathematics
1 answer:
Fudgin [204]2 years ago
3 0

Answer:

<h2><u><em>x=3 or x=−4</em></u></h2>

Step-by-step explanation:

when a number x is added to it's square, the total is 12. find two possible values of x

x+x^2=12

x^2+x=12

x^2+x−12=12−12

x^2+x−12=0

(x−3)(x+4)=0

x−3=0 or x+4=0

x=3 or x=−4

x=3 or x=−4

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The question is in the image below.
sineoko [7]

Answer:

The Recursive Formula for the sequence is:

\:a_n=\frac{1}{5}\left(a_{n-1}\right)     ; a₁ = 125

Hence, option D is correct.

Step-by-step explanation:

We know that a geometric sequence has a constant ratio 'r'.

The formula for the nth term of the geometric sequence is

a_n=a_1\cdot r^{n-1}

where

aₙ is the nth term of the sequence

a₁ is the first term of the sequence

r is the common ratio

We are given the explicit formula for the geometric sequence such as:

a_n=125\left(\frac{1}{5}\right)^{n-1}

comparing with the nth term of the sequence, we get

a₁ = 125

r = 1/5

Recursive Formula:

We already know that

  • a₁ = 125
  • r = 1/5

We know that each successive term in the geometric sequence is 'r' times the previous term where 'r' is the common ratio.

i.e.

a_n=ra_{n-1}

Thus, substituting r = 1/5

\:a_n=\frac{1}{5}\left(a_{n-1}\right)  

and a₁ = 125.

Therefore, the Recursive Formula for the sequence is:

\:a_n=\frac{1}{5}\left(a_{n-1}\right)     ; a₁ = 125

Hence, option D is correct.

3 0
3 years ago
Please explain to me to have a better understsning. . .​
dem82 [27]

For the first one:

m is the slope, or how much the line goes up compared to goes right.  In this case, the line goes up 40 every time it goes right 10.  We write this as a fraction so 40/10, which simplifies to 4.  Therefore the equation would be y = 4x.

7 0
3 years ago
Consider a geometric sequence with a first term of 4 and a fourth term of -2.916.
Orlov [11]

Answer:

a) Find the common ratio of this sequence.

Answer: -0.82

b) Find the sum to infinity of this sequence.

Answer: 2.2

Step-by-step explanation:

nth term in geometric series is given by 4\ th \ term = ar^n-1\\-2.196 = 4r^{4-1} \\-2.196/4 = r^{3} \\r = \sqrt[3]{0.549} \\r = 0.82

where

a is the first term

r is the common ratio and

n is the nth term

_________________________________

given

a = 4

4th term = -2.196

let

common ratio of this sequence. be r

4\ th \ term = ar^n-1\\-2.196 = 4r^{4-1} \\-2.196/4 = r^{3} \\r = \sqrt[3]{-0.549} \\r = -0.82

a) Find the common ratio of this sequence.

answer: -0.82

sum of infinity of geometric sequence is given by = a/(1-r)

thus,

sum to infinity of this sequence = 4/(1-(-0.82) = 4/1.82 = 2.2

4 0
3 years ago
5h+3 - j; use h = 6, and j = 1
olga55 [171]

Answer:

32

Step-by-step explanation:

lets substitute the appropriate values in the equation:

5h+3 - j    h= 6    j=1 , so we have:

5*6 +3 -1

30 +3 -1

32

7 0
2 years ago
Read 2 more answers
Simplify<br> l3r-15l if r&lt;5<br> SOLVE NOW PLEASE
katrin [286]

Answer:

-3r + 15 ---> answer

Step-by-step explanation:

r < 5

You are going to multiply both sides with 3. The reason being is that 3 is a positive number and the equality sign will not change if you use +3.

3r < 15

Now, subtract 15 from both sides, you will get this:

3r < 15

-15   -15

-------------

3r — 15 < 0

Lastly, using the Modulus function, we are going to add a negative sign to the content of our previous step because it's already negative.

So, -3r + 15 is the final solution if r < 5 in the given equation of l3r-15l

5 0
3 years ago
Read 2 more answers
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