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gizmo_the_mogwai [7]
2 years ago
12

Kamil has 72 baseball cards. He wants to put the cards

Mathematics
1 answer:
mars1129 [50]2 years ago
6 0
You would use 72/9 , ( division ).
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Stephanie and alejandro
Elena-2011 [213]

Answer:

Stephanie saved

Step-by-step explanation:

x+4x=15600

5x=15600

divide by 5 on both sides

you get 3120

since stephanie got 4 times more, you multiply 3120*4 and get 12480

therefore, Alejandro saved 3120

: )

4 0
2 years ago
You spin the spinner once.<br> What is P(6)?
lyudmila [28]

Answer:

1/2 for red, 1/4 for blue, or if you are speaking of both together it is 3/4

Step-by-step explanation:

4 0
3 years ago
Multiply. (7x-4)(4x-3)
dlinn [17]

<u>Your answer is 28x^2-37x+12</u>

<u>1) Use the FOIL method: (a+b)(c+d)=ac+ad+bc+bd</u>

28x^2-21x-16x+12

<u>2) Collect like terms</u>

28x^2+(-21-16x)+12

<u>3) Simplify</u>

28x^2-37x+12


7 0
2 years ago
Read 2 more answers
One of the digits of a two digit number is three times the other digit. If you interchange the digits of this two digit number a
STatiana [176]

Answer:

62

Step-by-step explanation:

well, we start by expressing the number:

a b

we understand that using the above expression, the value of the number is 10a + b

using the information in the question,

a = 3b (1)

and,

11b + 11a = 88 (2) (derived using 10a + b form)

hence, when substituting (1) into (2):

11b + 33b = 88

44b = 88

b = 2 (3)

sub (3) into (1)

a = 6

hence, the number is 62

3 0
2 years ago
Imagine that you need to compute e^0.4 but you have no calculator or other aid to enable you to compute it exactly, only paper a
labwork [276]

Answer:

0.0032

Step-by-step explanation:

We need to compute e^{0.4} by the help of third-degree Taylor polynomial that is expanded around at x = 0.

Given :

e^{0.4} < e < 3

Therefore, the Taylor's Error Bound formula is given by :

$|\text{Error}| \leq \frac{M}{(N+1)!} |x-a|^{N+1}$   , where $M=|F^{N+1}(x)|$

         $\leq \frac{3}{(3+1)!} |-0.4|^4$

         $\leq \frac{3}{24} \times (0.4)^4$

         $\leq 0.0032$

Therefore, |Error| ≤ 0.0032

4 0
2 years ago
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