Answer :
no. of days used to repair 1250m of road = 5
no. of days used to repair 1m of road = 5/1250
no. of days used to repair 8000m of road (8*1000m ) = 5/1250*8000= 32 days
Answer:
583 rounded to the nearest whole number
Step-by-step explanation:
other wise 583.3333333333333333333333333333
42 (1- 25/100) = 63/2 = 31.5 dollars
answer is $31.50
hope it helps
Answer:
Step-by-step explanation:Here's li
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