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Maurinko [17]
3 years ago
5

Please help!! First person gets award or whatever it is!! Awarding 10 points

Mathematics
1 answer:
Gekata [30.6K]3 years ago
5 0
2c^2
Square root

Brainly wants me to have 20 characters so don’t mind the text down here

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Review:
alex41 [277]

Answer:

Step-by-step explanation:

Well 6 to the second power is when you multiply 6 x 6 = 36

And ab= -320

7 0
3 years ago
A hardware store rents vacuum cleaners that customers may use for part or all of a day, before returning. The store charges a fl
Vsevolod [243]

Answer:

Total rental cost is:

y = Bx + M

where x is number of additional hours, y is total cost, M is fixed fee, and B are  is amount that is charged per hour.

Step-by-step explanation:

Let amount of flat fee = M

let hourly rate = B

Total rental cost = ?

As given the store charges a flat fee plus an hourly rate:

                                      ⇒    y = Bx + M

where x is number of additional hours, y is total cost, M is fixed fee, and B are  is amount that is charged per hour.

5 0
3 years ago
Bryan owes his friend more than $1,610 from a loan. Bryan has already paid his friend back $206 and continues to pay him $156 ea
Genrish500 [490]
Owes more than 1425
owe>1425

owed musbe be equal to how much he paid back

paid back 210

and 153 per month is paid back (represent number of months by x)
so
owe=210+152x

210+153x>1425
153x+210>1425

Don't know if this is right or if it helps but
6 0
3 years ago
Read 2 more answers
Solve for y x=y^2+4y
Lorico [155]
x=y^2+4y\\ y^2+4y-x=0\\\Delta=4^2-4\cdot1\cdot(-x)=16+4x\\\\
1.\ \Delta0\\
\sqrt{\Delta}=\sqrt{16+4x}=\sqrt{4(4+x)}=2\sqrt{x+4}\\
y_1=\frac{-4-2\sqrt{x+4}}{2\cdot1}=-2-\sqrt{x+4}\\
y_2=\frac{-4+2\sqrt{x+4}}{2\cdot1}=-2+\sqrt{x+4}\\

-----------------------------------------------------

x=y^2+4y\\ y^2+4y-x=0\\
y^2+4y+4-4-x=0\\
(y+2)^2=x+4\\
y+2=\sqrt{x+4} \vee y+2=-\sqrt{x+4}\\
y=-2+\sqrt{x+4} \vee y=-2-\sqrt{x+4}\\

4 0
4 years ago
9x - 4y? +72x–24y— 36–0
earnstyle [38]
Not is posible because no exist a igualty
3 0
3 years ago
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