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2 years ago

6

How to factor by grouping:

^{3} - 75x" alt="{27x}^{3} - 75x" align="absmiddle" class="latex-formula">

1 answer:

Nataly [62]2 years ago

5 0

Answer:

3 x (3 x - 5) (3 x + 5)

Step-by-step explanation:

Factor the following:

27 x^3 - 75 x

Factor 3 x out of 27 x^3 - 75 x:

3 x (9 x^2 - 25)

9 x^2 - 25 = (3 x)^2 - 5^2:

3 x (3 x)^2 - 5^2

Factor the difference of two squares. (3 x)^2 - 5^2 = (3 x - 5) (3 x + 5):

Answer: 3 x (3 x - 5) (3 x + 5)

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A and B together complete a work in 20days. They worked together for 5days and B leaves. How long will A takes to finish the rem

andreev551 [17]

Answer:

27 days

Step-by-step explanation:

A alone, rate per day = 1/36

A and B together, rate per day = 1 / 20

Total Workdone for 5 days :

1/ 20 * 5 = 5 / 20 = 1/4

Fraction of work left :

1 - 1/4 = 3/4

3 / 4 * 36 /1

= (3 * 36) / 4

= 108 / 4

= 27 days

3 0

2 years ago

You are going to visit a relative out of town and want to go to the gym while visiting. Hunkey Heros charges a registration fee

iragen [17]

The number of months when the gyms cost the same is 5 months.

<h3>When would the cost be the same?</h3>

Total cost of joining the gym = registration fee + (cost per month x number of months)

Hunkey Heros = $50 + $20m
Zipity-zapity- zap-that-fat = $70 + $10m

When the gyms costs are the same, the two above equations would be equal to each other:

50 + 20m = 70 + 10m

20m - 10m = 70 - 20

10m = 50

m = 50 / 10

m = 5

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4 0

1 year ago

Which pair of funtions is not a pair of inverse functions? please help!!

antiseptic1488 [7]

Answer:

$f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

<u>case A)</u> $f(x)=\frac{x+1}{6} , g(x)=6x-1$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y+1}{6}$

Isolate the variable y

$6x=y+1$

$y=6x-1$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=6x-1$

therefore

f(x) and g(x) are inverse functions

<u>case B)</u> $f(x)=\frac{x-4}{19} , g(x)=19x+4$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y-4}{19}$

Isolate the variable y

$19x=y-4$

$y=19x+4$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=19x+4$

therefore

f(x) and g(x) are inverse functions

<u>case C)</u> $f(x)=x^{5}, g(x)=\sqrt[5]{x}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=y^{5}$

Isolate the variable y

fifth root both members

$y=\sqrt[5]{x}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\sqrt[5]{x}$

therefore

f(x) and g(x) are inverse functions

<u>case D)</u> $f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y}{y+20}$

Isolate the variable y

$x(y+20)=y$

$xy+20x=y$

$y-xy=20x$

$y(1-x)=20x$

$y=20x/(1-x)$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=20x/(1-x)$

$\frac{20x}{1-x}\neq \frac{20x}{x-1}$

therefore

f(x) and g(x) is not a pair of inverse functions

7 0

2 years ago

Read 2 more answers

In the formula, P3 = Div / R - g, the dividend is for period:

Ksenya-84 [330]

If your choices are the following:
A. OneB. TwoC. ThreeD. FourE. Five

Then the answer would be letter D. Four.

7 0

2 years ago

A student has 54 coins in a bank. There are only quarters, nickels, and dimes in the bank. If there are twice as many dimes as q

r-ruslan [8.4K]

The student would have 18 dimes in the bank.. 54 coins. x+2x+3x=54
6x=54

18 dimes,
9 quarters
27 nickles.

5 0

2 years ago