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Shalnov [3]
3 years ago
7

Which polynomial is equivalent to 8x3+12x/2x when x≠0?

Mathematics
1 answer:
ANTONII [103]3 years ago
6 0

Answer: look at the picture

Step-by-step explanation: Hope this help :D

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Dan counted all the coins in his bank, and he had 72 quarters. can he exchange the quarters for an even amount of dollar bills?
Vladimir [108]
There are 4 quarters in a dollar. If you divide 72 by 4 and you do not get a remainder then he can.
8 0
3 years ago
Pls help with this question I don't know the answer. Don't put wrong answers pls.
Lapatulllka [165]

Answer:

-2 I believe. because the 1st exponent would make it 9, and then you'd remove 2

Step-by-step explanation:

I hope this is correct and helpful, I tried my best! <3

7 0
3 years ago
Evaluate ( 4 upon 3 ) -2<br><br><br>please amswer fast​
Taya2010 [7]
<h2><u>Solution</u></h2>

\frac{4}{3}  - 2 \\  \\   = \frac{4 - 6}{ 3}  \\  \\  =  \frac{ - 2}{3}

<h3>Hope This Helps You ❤️</h3>
6 0
3 years ago
Determine whether each of the following functions is even, odd, or neither even nor odd.
Illusion [34]

Answer:

A.) Even.

Step-by-step explanation:

If a function is an even function, then

F(-x) = f(x)

Also, if a function is an odd function, then, f(-x) = -f(x)

You are given the below function

f(x) = 1 + 3x^2 − x^4

Let x = 2

Substitute 2 for x in the function

F(x) = 1 + 3(2)^2 - (2)^4

F(x) = 1 + 3(4) - 16

F(x) = 1 + 12 - 16

F(x) = -3

Also, Substitute -2 for x in the function

F(x) = 1 + 3(-2)^2 - (-2)^4

F(x) = 1 + 3(4) - 16

F(x) = 1 + 12 - 16

F(x) = -3

Since f(-x) = f(x), we can conclude that

F(x) = 1 + 3x^2 - x^4 is even

5 0
3 years ago
Use the multiplier method to increase 88 pounds by 14% you must show your working
Komok [63]

Answer:

100.32

Step-by-step explanation:

First, we have to find 14% of 88

14% of 88 is = 88 x 14/100

                  = 12.32

Now we have to increase the number 88 by 14%, which means we have to add 14% of 88 (12.32) to the given number (88)  

88 + (14% of 88)

= 88 + 12.32

=100.32 pounds

6 0
2 years ago
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