Please help..............

Mathematics

1 answer:

Vikentia [17]3 years ago

5 0

Answer:

The first one.

Step-by-step explanation:

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A line passes through (3, –2) and (8, 2).

EleoNora [17]

The point-slope form:
$y-y_1=m(x-x_1)$
m - slope
(x₁,y₁) - point

$(3,-2) \\
x_1=3 \\ y_1=-2 \\ \\
(8,2) \\
x_2=8 \\ y_2=2 \\ \\ \hbox{the slope:} \\
m=\frac{y_2-y_1}{x_2-x_1}=\frac{2-(-2)}{8-3}=\frac{2+2}{5}=\frac{4}{5} \\ \\ \hbox{the point-slope form:} \\
y-y_1=m(x-x_1) \\
y-(-2)=\frac{4}{5}(x-3) \\
\boxed{y+2=\frac{4}{5}(x-3)}$

$\hbox{the standard form:} \\
y+2=\frac{4}{5}(x-3) \\
y+2=\frac{4}{5}x-\frac{12}{5} \\
-\frac{4}{5}x+y=-\frac{12}{5}-2 \ \ \ |\times 5 \\
-4x+5y=-12-10 \\
\boxed{-4x+5y=-22}$

The answer is D.

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4 years ago

Determine whether the lines are parallel, perpendicular, or neither. x = 3 and y = 4

Katyanochek1 [597]

I think they’re perpendicular lines

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A triangular space between three streets has measurements shown. how much new curbing will be needed to go around the space? ho

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If the right triangle has legs with lengths 42 m and 34 m and the hypotenuse with length 54 m, then you need:
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All given choices are right.

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Answer:

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