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larisa86 [58]
3 years ago
11

At that velocity voyager 1 would have traveled 547,500,000 kilometers in a year. Whats that in scientific notation ?

Mathematics
1 answer:
andrey2020 [161]3 years ago
7 0

Answer: 5.475 x 10^8

Step-by-step explanation: The number has to be in between 1 and 10 so you move your decimal as many times as you need to. In this situation it is 8, so that is your power

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Two vectors A⃗ and B⃗ are at right angles to each other. The magnitude of A⃗ is 5.00. What should be the length of B⃗ so that th
creativ13 [48]

Answer:

Length of B is 7.4833

Step-by-step explanation:

The vector sum of A and B vectors in 2D is

C=A+B=(a_1+b_1,a_2+b_2)

And its magnitude is:

C=\sqrt{(a_1+b_1)^2+(a_2+b_2)^2} =9

Where

a_1=Asinx

a_2=Acosx

b_1=Bsin(x+90)

b_2=Bcos(x+90)

Using the properties of the sum of two angles in the sin and cosine:

b_1=Bsin(x+90)=B(sinx*cos90+sin90*cosx)=Bcosx

b_2=Bcos(x+90)=B(cosx*cos90-sinx*sin90)=-Bsinx

Sustituying in the magnitud of the sum

C=\sqrt{(Asinx+Bcosx)^2+(Acosx-Bsinx)^2} =9

C=\sqrt{A^2sin^2x+2ABsinxcosx+B^2cos^2x+A^2cos^2x-2ABsinxcosx+B^2sin^2x} =9

C=\sqrt{A^2(sin^2x+cos^2x)+B^2(cos^2x+sin^2x)}

C=\sqrt{A^2+B^2} =9

Solving for B

A^2+B^2 =9^2

B^2 =9^2-A^2

Sustituying the value of the magnitud of A

B^2=81-5^2=81-25=56

B= 7. 4833

8 0
3 years ago
1. Find the LCM of the given numbers.<br> 4 and 7
GuDViN [60]

Answer:

The LCM of (4,7) is 28

Step-by-step explanation:

7 0
2 years ago
Vern drinks three 6-packs of beer each week at a cost of $7
I am Lyosha [343]

Answer:

Vern’s total beer cost for the year is 52×3×$7 = $1092. On an annual basis basis,his beer expense is$1092/$700= 156%of his texbook expense

hope i helped

-LVR

5 0
3 years ago
Find the smallest value of n such that the LCM of n and 15 is 45
krek1111 [17]

Answer:45


Step-by-step explanation:

9 and 15 both go into 45, and 45 is the LCM of those numbers.

6 0
3 years ago
Read 2 more answers
A) Describe the congruence shortcut (postulate/theorem) that could be used to prove that ΔABC≅ΔDEF
bixtya [17]

Answer:

A. By the Side-Side-Side (SSS) Congruence Theorem, ΔABC ≅ ΔDEF.

B. \overline{AB} \cong \overline{DE}

\overline{BC} \cong \overline{EF}

\overline{AC} \cong \overline{DF}

Step-by-step explanation:

a. From the diagram given, it shows that all three sides of ∆ABC are congruent to all the three corresponding sides of ∆DEF.

Therefore, by the Side-Side-Side (SSS) Congruence Theorem, ΔABC ≅ ΔDEF.

b. The sides that are congruent in the ∆s given that applies to the SSS Congruence Theorem are:

\overline{AB} \cong \overline{DE}

\overline{BC} \cong \overline{EF}

\overline{AC} \cong \overline{DF}

6 0
3 years ago
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