Heba ate \dfrac{1}{12} 12 1 start fraction, 1, divided by, 12, end fraction of a box of cereal. Now the box is \dfrac{3}{4} 4 3 start fraction, 3, divided by, 4, end fraction full. What fraction of a full box was there before Heba ate
1 answer:
9514 1404 393
Answer:
5/6
Step-by-step explanation:
If q is the quantity of cereal in the box before Heba ate some, the problem tells us ...
q - 1/12 = 3/4
q = 3/4 + 1/12 = 9/12 + 1/12 = 10/12
q = 5/6
There was 5/6 of a box before Heba ate .
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