5x+30=7x+20<br> Bbbbnnvvvcvhbx

Addition and Subtraction Equations<br>Solve<br>6+ (w-10)=5

IrinaVladis [17]

Answer:

w = 9

Step-by-step explanation:

Given

6 + (w - 10) = 5, that is

6 + w - 10 = 5

w - 4 = 5 ( add 4 to both sides )

w = 9

8 0

3 years ago

A piece of paper is randomly selected from a stack that contains 15 small, 44 large, and 20 extra large pieces.

yKpoI14uk [10]

Answer: The true statement is (A) P(extra large)≈0.25.

Step-by-step explanation:

Given that a piece of paper is randomly selected from a stack that contains 15 small, 44 large, and 20 extra large pieces.

We are to select the true statement.

Let S be the sample space for the experiment of choosing a piece.

Then, n(S) = 15 + 44 + 20 = 79.

Let A, B and C denote the events of choosing a small piece, a large piece and an extra large piece respectively.

So, n(A) = 15, n(B) = 44 and n(C) = 20.

Therefore, we have

Thus, the true statement is P(extra large)≈0.25.

Option (A) is correct

3 0

3 years ago

Help me plz and explain

Verdich [7]

58.50 - 45 = 13.50

13.50 / 45 x 100 = 30%

answer: mark up 30%

8 0

3 years ago

What is 4(3+x) and how do I solve it

anastassius [24]

Answer:

12 + 4x

Step-by-step explanation:

To solve this you would have to use the distributive property.

The problem would basically go like this.

4 (3+x)

(Distribute)

(4x3) (4 x X)

4x3 = 12, 4 x x = 4x

So the answer would be 12 +4x

Hope this helps :)

3 0

3 years ago

Read 2 more answers

A car company claims that its cars achieve an average gas mileage of at least 26 miles per gallon. A random sample of eight cars

motikmotik

Answer:

$t=\frac{25.5-26}{\frac{1}{\sqrt{8}}}=-1.414$

The degrees of freedom are given by:

$df=n-1=8-1=7$

The p value for this case is given by:

$p_v =P(t_{(7)}$

Since the p value is higher than the significance level of 0.06 we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly less than 25.5 and then the claim makes sense

Step-by-step explanation:

Information given

$\bar X=25.5$ represent the sample mean

$s=1$ represent the sample standard deviation

$n=8$ sample size

$\mu_o =26$ represent the value to verify

$\alpha=0.06$ represent the significance level

t would represent the statistic (variable of interest)

$p_v$ represent the p value

Hypothesis to est

We want to test if the true mean is at least 26 mpg, the system of hypothesis would be:

Null hypothesis: $\mu \geq 25.5$

Alternative hypothesis: $\mu < 25.5$

The statistic for this case is given by;

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{25.5-26}{\frac{1}{\sqrt{8}}}=-1.414$

The degrees of freedom are given by:

$df=n-1=8-1=7$

The p value for this case is given by:

$p_v =P(t_{(7)}$

Since the p value is higher than the significance level of 0.06 we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly less than 25.5 and then the claim makes sense

3 0

4 years ago

5x+30=7x+20 Bbbbnnvvvcvhbx