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irga5000 [103]
3 years ago
7

Emil's backpack weighs 6 3/8 pounds. He removes a book that weighs 3/4 pounds. Then he removed a book that weighs 1/2 pound. How

much Emil's backpack weigh now? in the simplest form
Mathematics
1 answer:
Alex_Xolod [135]3 years ago
6 0

Answer:

2.5625

Step-by-step explanation:

So 6 3/8- 1/2 -3/4= 5.125 5.125 divided 2 = 2.5625


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Marsha spends 150 minutes a night doing homework.
kodGreya [7K]

Answer:

70%

Step-by-step explanation:

Maths homework takes 1/6×150mins

=150/6=25 mins

science homework takes 20/100×150

=3000/100

=30mins

Language Arts homework uses 1/3×150

=150/3

=50 mins

percent of time left for Marsha's social studies homework=total time used / original time

=(25+30+50)mins

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=0.7×100

=70%

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2 years ago
I don’t get this one help me please
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...........................................................(4 yrd and 2ft ) there is 3 ft in a yard 14 divided by 3 is 4 remainder 2 
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8=72<br> 2=6<br> 5=30<br> 9=?<br><br> what is the value of ?
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Answer:

108?

Step-by-step explanation:

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3 years ago
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Please solve these questions for me. i am having a difficult time understanding.
s2008m [1.1K]

Answer:

1) AD=BC(corresponding parts of congruent triangles)

2)The value of x and y are 65 ° and 77.5° respectively

Step-by-step explanation:

1)

Given : AD||BC

AC bisects BD

So, AE=EC and BE=ED

We need to prove AD = BC

In ΔAED and ΔBEC

AE=EC (Given)

\angle AED = \angel BEC ( Vertically opposite angles)

BE=ED (Given)

So, ΔAED ≅ ΔBEC (By SAS)

So, AD=BC(corresponding parts of congruent triangles)

Hence Proved

2)

Refer the attached figure

\angle ABC = 90^{\circ}

In ΔDBC

BC=DC (Given)

So,\angle CDB=\angle DBC(Opposite angles of equal sides are equal)

So,\angle CDB=\angle DBC=x

So,\angle CDB+\angle DBC+\angle BCD = 180^{\circ} (Angle sum property)

x+x+50=180

2x+50=180

2x=130

x=65

So,\angle CDB=\angle DBC=x = 65^{\circ}

Now,

\angle ABC = 90^{\circ}\\\angle ABC=\angle ABD+\angle DBC=\angle ABD+x=90

So,\angle ABD=90-x=90-65=25^{\circ}

In ΔABD

AB = BD (Given)

So,\angle BAD=\angle BDA(Opposite angles of equal sides are equal)

So,\angle BAD=\angle BDA=y

So,\angle BAD+\angle BDA+\angle ABD = 180^{\circ}(Angle Sum property)

y+y+25=180

2y=180-25

2y=155

y=77.5

So, The value of x and y are 65 ° and 77.5° respectively

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