Let's say that the diameter was 1/2 mile. So the diameter is 1/2, then you need to find the circumference, aka perimeter of the circle. So 1/2 times 3.14 = 1.57 miles So then you would do 1.57/2 = .785 of an hour If you round to nearest tenth The answer is .8 of an hour.
Take the log (base 4) of both sides of the equation.



The appropriate choice is ...
m = -11/4
Step-by-step explanation:
When it says x = something, that basically means to replace the x with whatever it says x equals.
x = 0. Equation /. 3 x 0 = 0 + 1 = 1. Y = 1
x = -1. Equation/. 3 x -1 = -3 + 1 = -2. Y = -2
x = 2. Equation/. 3 x 2 = 6 + 1 = 7. Y = 7
Hope this helps!! (:
Answer:
48∛9 ft²
Step-by-step explanation:
The length (L) and width (W) are given by:
![L = 4\sqrt[3]{24}\\ W= 6\sqrt[3]{3}](https://tex.z-dn.net/?f=L%20%3D%204%5Csqrt%5B3%5D%7B24%7D%5C%5C%20W%3D%206%5Csqrt%5B3%5D%7B3%7D)
Since this is a rectangular region, the area is given by:
![A=L*W=L \\A=4\sqrt[3]{24}* 6\sqrt[3]{3}\\A=24\sqrt[3]{72}\ ft^2](https://tex.z-dn.net/?f=A%3DL%2AW%3DL%20%5C%5CA%3D4%5Csqrt%5B3%5D%7B24%7D%2A%206%5Csqrt%5B3%5D%7B3%7D%5C%5CA%3D24%5Csqrt%5B3%5D%7B72%7D%5C%20ft%5E2)
The answer can be further simplified by factoring as follows:
![A=24\sqrt[3]{72} = \\A=24\sqrt[3]{2*2*2*3*3}= 24\sqrt[3]{2^3*9}\\A=48\sqrt[3]{9}\ ft^2](https://tex.z-dn.net/?f=A%3D24%5Csqrt%5B3%5D%7B72%7D%20%3D%20%5C%5CA%3D24%5Csqrt%5B3%5D%7B2%2A2%2A2%2A3%2A3%7D%3D%2024%5Csqrt%5B3%5D%7B2%5E3%2A9%7D%5C%5CA%3D48%5Csqrt%5B3%5D%7B9%7D%5C%20ft%5E2)
The exact area is its simplest form is 48∛9 ft²
The geometric mean of two numbers x and y is √(xy).
So, if the geometric mean of 3 and a is 9 =>
9 = √(3a)
=> 9^2 = 3a
=> a = 9^2 / 3
a = 81 / 3
a = 27
Answer: the value of a is 27.