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Mashcka [7]
3 years ago
10

I need help with homework these two problems I'm having trouble with

Mathematics
1 answer:
ycow [4]3 years ago
3 0
The gcf of 25 and 60 is 5
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A right triangle has legs of lengths 6 and 15 inches. Find the length of the hypotenuse (nearest tenth).​
zubka84 [21]

Answer:

The length of the hypotenuse is 16.2 inches.

Step-by-step explanation:

c^{2} = a^{2} + b^{2}

c^{2} = 6^{2} + 15^{2}

c^{2} = 36 + 225

c^{2} = 261

\sqrt{c^{2} } = \sqrt{261}

c = 16.2

8 0
3 years ago
Can anybody help please i will help them also if they help me
kotegsom [21]
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3- 0:101, 0/101
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3 years ago
A teacher printed 720 copies. How long did it take to print?
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3 years ago
Use pictures or words to explain how you would use the sum of 13 to show how to add in any order
zheka24 [161]
9 + 4 or 4 + 9. They both equal 13.
4 0
3 years ago
Read 2 more answers
If θ is an angle in standard position that terminates in Quadrant III such that tanθ = 5/12, then sinθ/2 = _____
babunello [35]

Answer:

sin θ/2=5√26/26=0.196

Step-by-step explanation:

θ ∈(π,3π/2)

such that

θ/2 ∈(π/2,3π/4)

As a result,

0<sin θ/2<1, and

-1<cos θ/2<0

tan θ/2=sin  θ/2/cos θ/2

such that

tan θ/2<0

Let

t=tan θ/2

t<0

By the double angle identity for tangents

2 tan θ/2/1-(tanθ /2)^2  = tanθ

2t/1-t^2=5/12

24t=5 - 5t^2

Solve this quadratic equation for t :

t1=1/5 and

t2= -5

Discard t1 because t is not smaller than 0

Let s= sin θ/2

0<s<1.

By the definition of tangents.

tan θ/2= sin θ/2/ cos θ/2

Apply the Pythagorean Algorithm to express the cosine of θ/2 in terms of s. Note the cos θ/2 is expected to be smaller than zero.

cos θ/2 = -√1-(sin θ/2)^2 = - √1-s^2

Solve for s.

s/-√1-s^2 = -5

s^2=25(1-s^2)

s=√25/26 = 5√26/26

Therefore

sin θ/2=5√26/26=0.196....

7 0
4 years ago
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