Call (F) the age of the father and (J) the age of Julio
The F & J are related in this way: F=4J
Now you have a restriction in the form of inequality: The sum of both ages has to be greater or equal than 55.
Algebraically that is: F + J ≥ 55
You can substitute F with 4J to find the solution for J:
4J + J ≥ 55
5J ≥ 55
Now divide both sides by 5
5J/5 ≥ 55/5
J ≥ 11
That Imposes a lower boundary for the value of J of 11, meaning that the youngest age of Julio can be 11
14.2 - 2.2 - 1
12 -1
11
Hope this helps
It would be still be X. Any number times 1 is that number. For example 3x1=3 and 325x1=325 :)
6 times 12 is 72 so 14 times 12 would be 168 if that is what you are looking for. So for that y=168 :-)
The GCF of 26 and 70 is 2.
