Question

Two sides of a triangle measure 6 cm and 8 cm. What is the possible measurement of the 3rd side of the triangle

Answer 1

Step-by-step explanation:

If the triangle is right, we can use Pitagora

We can have 2 results

1.

$\sqrt{ {6}^{2} + {8}^{2} } = \\ = \sqrt{36 + 64} = \\ = \sqrt{100} \\ = 10$

2.

$\sqrt{ {8}^{2} - {6}^{2} } = \\ = \sqrt{64 - 36} = \\ = \sqrt{28 } \\ = 2 \sqrt{7}$