Answer:
Step-by-step explanation:
p(A) = a^3 + 3a^2 + 9a + 27
put brackets around the 1st and second terms and another set around the 3rd and 4th
P(a)= (a^3 + 3a^2) + (9a + 27)
Using the distributive property, pull out the common factor for each of the 2 terms that contain the brackets.
P(a) = a^2 ( a + 3) + 9(a + 3)
Let a + 3 = x
P(a) = a^2x + 9x
Put brackets around these 2 terms
P(a)= x(a^2 + 9)
Substitute a + 3 for x
P(a) = (a + 3) ( a^2 + 9)
1. -2 I hope that helps a little bit
Answer:
work is shown and pictured
The answer is C make it half, you will always get the other half of the number
108=103e^(5k)
108/103=e^(5k) take the natural log of both sides
ln(108/103)=5k
k=ln(108/103)/5
k≈0.00948
P=103e^(12*0.00948)
P≈115 million (to nearest million)
