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kotegsom [21]
3 years ago
13

Un camión pesa 875 kg la diferencia entre el peso del camión vacío y el peso de la carga que lleve no debe ser inferior a 415 kg

, si hay que cargar 4 cajas iguales cuanto puede pesar con lo máximo cada una de ellas para poder llevarlas en el camión? Ayuda por favor
Mathematics
1 answer:
Arturiano [62]3 years ago
8 0

Answer:

The weight of each box must be less than 115 kg to be carried in the truck.

Step-by-step explanation:

The weight of the truck is, T = 875 kg.

Let the weight of one box be <em>x</em> kg.

Given:

875-4x>415 kg.

Solve the above inequality for <em>x</em> as follows:

875-4x>415\\-4x>415-875\\-4x>-460\\x

As the weight of a box cannot be less than 0, the range of <em>x</em> is (0, 115).

Thus, the weight of each box must be less than 115 kg to be carried in the truck.

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7 0
3 years ago
The cost of C (in dollars) of making n watches is represented by C=15n+85. How many watches are made when the cost is $385?
hichkok12 [17]

well...

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4 0
3 years ago
A programmer wants to display how the shape of a rectangle with a fixed perimeter of 375 inches can be changed by varying the re
Nina [5.8K]

Answer:

A = 187.5L - L^2

So,

g(l) = 187.5l - l^2

Step-by-step explanation:

The perimeter of a rectangle is given by:

P = 2(L + B)

Where P = perimeter

L = Length

B = Width

Making B the subject of formula, we have;

B = P/2 - L ......1

The area of a rectangle is:

A = L × B ........2

Substituting equation 1 to 2.

A = L × (P/2 - L)

A = LP/2 - L^2 .......3

Given that the perimeter P = 375 inches

A = L(375)/2 - L^2

A = 187.5L - L^2

So,

g(l) = 187.5l - l^2

7 0
3 years ago
If the class started at 11:30 A.M. and ended at 12:25 P.M., how long did the class last?
Delicious77 [7]

Answer: 55 minutes

Step-by-step explanation:

If the class started at 11:30 A.M. and ended at 12:25 P.M., how long did the class last? 55 minutes

***If you found my answer helpful, please give me the brainliest, please give a nice rating, and the thanks ( heart icon :) ***

3 0
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