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3 years ago

7

What is t in t/3 = 4/9?

1 answer:

SCORPION-xisa [38]3 years ago

7 0

Answer:

$t = \frac{4}{3}$

Step-by-step explanation:

1) Multiply both sides by 3.

$t = \frac{4}{9} \times 3$

2) Use this rule: a/b × c = ac/b.

$t = \frac{4 \times 3}{9}$

3) Simplify 4 × 3 to 12.

$t = \frac{12}{9}$

4) Simplify 12/9 to 4/3.

$t = \frac{4}{3}$

Therefor, the answer is, t = 4/3.

and in decimal form it would be, 1.333333.

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Find the surface area of the part of the sphere x2+y2+z2=81 that lies above the cone z=x2+y2−−−−−−√

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Parameterize the part of the sphere by

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with $0\le u\le2\pi$ and $0\le v\le\dfrac\pi4$ . Then

$\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|=81\sin v\,\mathrm du\,\mathrm dv$

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$\displaystyle\iint_S\mathrm dS=81\int_{v=0}^{v=\pi/4}\int_{u=0}^{u=2\pi}\sin v\,\mathrm du\,\mathrm dv=81(2\pi)\left(1-\dfrac1{\sqrt2}\right)=(162-81\sqrt2)\pi$

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4 years ago

How many angles between 0° and 360° have a tangent of<br> of 2/3?

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2 years ago

Help please!! Based on Pythagorean identities, which equation is true ??

alexgriva [62]

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3 years ago

Select the correct option from the menu.

Elina [12.6K]

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3 years ago

21. Paul has $900 to invest in a savings account that has an annual interest rate of 1.8%, and a money market account that pays

Iteru [2.4K]

The polynomial that gives the interest earned after a year will have variables, exponents and constants that are joined by operators.

The interest earned after one year is <u>0.018·x</u>

Reasons:

The amount Paul has to invest = $900

The annual interest rate from the savings account = 1.8%

The amount the money market account pays per year = 4.2 %

Required: The polynomial for the interest Paul earned by investing <em>x</em> dollars in the savings account.

Solution:

The interest earned is found using the compound interest formula as follows;

$\displaystyle A = \mathbf{P \cdot \left(1 + \frac{r}{n} \right)^{n \cdot t}}$

Where;

A = The amount in the account after one year

P = The original amount invested = x

r = The interest rate offered on the investment = 1.8% = 0.018

t = The time of the investment = 1 year

n = The number of times of application of the interest per period = Once per year

Which gives;

Interest = Amount earned = A - P

Therefore;

$\displaystyle Interest, \ I = \mathbf{P \cdot \left(1 + \frac{r}{n} \right)^{n \cdot t} - P}$

Plugging in the values gives;

$\displaystyle I = x \cdot \left(1 + \frac{0.018}{1} \right)^{1 \times 1} - x = x \cdot 1.018^1 - x = 1.018 \cdot x - x = 0.018 \cdot x$

The polynomial equation is therefore;

Interest, I = 0.018·x

Using the simple interest formula, we have;

$\displaystyle Interest = \mathbf{\frac{P \times r \times t}{100}}$

Which gives;

$\displaystyle Interest = \frac{x \times 1.8 \times 1}{100} = 0.018 \cdot x$

Interest earned by investing in the savings account for one year, I = 0.018·x

The polynomial representing the interest earned is <u><em>I</em></u><u> = 0.018·x</u>

Learn more here:

brainly.com/question/11314161

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2 years ago