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3 years ago

Need Help on Algebra 2 Question To Finish My Unit Exam (10.12)

Mathematics

1 answer:

TEA [102]3 years ago

5 0

Answer:

3rd option

Step-by-step explanation:

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Write this as a power of 2. ex ( 2^n) requires knowledge of negative exponents

Snowcat [4.5K]

Answer:

Step-by-step explanation:

$\frac{32}{ \sqrt[8]{16} } \\$

Simplify

$\frac{32}{1.414213562} \\ \\ = 22.627417$

Method 2 :

By rationalizing the denominator

7 0

3 years ago

If K = F( A + B ) , find “ A ” if F = 2 , B = 3 , K = 10

Oxana [17]

Answer:

The value of A is 2

Step-by-step explanation:

F = 2 , B = 3 , K = 10

K = F( A + B )

10 = 2(A + 3)

10 = 2A + 6

Now, Subtract 6 from each side we get,

10 - 6 = 2A + 6 - 6

4 = 2A

2A = 4

Now, divide both side by 2 we get,

2A/2 = 4/2

A = 2

Thus, The value of A is 2

<h3><u>FOR V</u><u>ERIFICATION</u><u> ONLY</u> :-</h3>

K = F( A + B )

10 = 2(2 + 3)

10 = 2(5)

10 = 10

L.H.S = R.H.S

Hence Proved!

<u>-TheUnknownScientist</u><u> 72</u>

7 0

3 years ago

Use matrices and elementary row to solve the following system:

LiRa [457]

I assume the first equation is supposed to be

$5x-3y+2z=13$

and not

$5x-3x+2x=4x=13$

As an augmented matrix, this system is given by

$\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\4&-2&4&12\end{array}\right]$

Multiply through row 3 by 1/2:

$\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\2&-1&2&6\end{array}\right]$

Add -1(row 2) to row 3:

$\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&5&5\end{array}\right]$

Multiply through row 3 by 1/5:

$\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&1&1\end{array}\right]$

Add -2(row 3) to row 1, and add 3(row 3) to row 2:

$\left[\begin{array}{ccc|c}5&-3&0&11\\2&-1&0&4\\0&0&1&1\end{array}\right]$

Add -3(row 2) to row 1:

$\left[\begin{array}{ccc|c}-1&0&0&-1\\2&-1&0&4\\0&0&1&1\end{array}\right]$

Multiply through row 1 by -1:

$\left[\begin{array}{ccc|c}1&0&0&1\\2&-1&0&4\\0&0&1&1\end{array}\right]$

Add -2(row 1) to row 2:

$\left[\begin{array}{ccc|c}1&0&0&1\\0&-1&0&2\\0&0&1&1\end{array}\right]$

Multipy through row 2 by -1:

$\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-2\\0&0&1&1\end{array}\right]$

The solution to the system is then

$\boxed{x=1,y=-2,z=1}$

5 0

3 years ago

Whats 3,465 in expanded form

dimulka [17.4K]

3000 +400+60+5 is the answer.hope I helped you

7 0

3 years ago

PLEASE HELP ME!!! I NEED HELP WITH GEOMETRY QUESTION ASAP!! DESPRATLY

BartSMP [9]

Answer:

The answer to your question is: y = -3x + 14

Step-by-step explanation:

Data

A (4, 2)

y = x/3 - 1

Perpendicular

original slope = 1/3

perpendicular slope = -3

Equation (y - y1) = m(x - x1)

(y - 2) = -3(x - 4)

y - 2 = -3x + 12

y = -3x + 12 + 2

y = -3x + 14

4 0

3 years ago