Ask question

Ask question

All categories

2 years ago

10

Scarlet stars a spelling class at 11:05 AM. the test is 1 hour and 5 minutes long. after the spelling test, scarlet has art clas

s for 1 hour and 40 minutes what time does scarlet art class end?

1 answer:

lorasvet [3.4K]2 years ago

3 0

Answer:

2:00 PM

Step-by-step explanation:

You might be interested in

(-4x-2)+1/2(12x-22) simplify

Ierofanga [76]

Answer:

2x - 13

Step-by-step explanation:

Step 1 :

1

Simplify —

2

Equation at the end of step 1 :

1

(-4x - 2) + (— • (12x - 22))

2

Step 2 : Pulling out like terms :

3.1 Pull out like factors :

12x - 22 = 2 • (6x - 11)

Step 3 :

Pulling out like terms :

3.1 Pull out like factors :

12x - 22 = 2 • (6x - 11)

Equation at the end of step 3 :

(-4x - 2) + (6x - 11)

6 0

2 years ago

Evaluate 5÷9(F - 32) when f=50

solmaris [256]

Answer:

10

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

7.13 g =<br>cg what is the answer

Zina [86]

Answer: 713 cg

Step-by-step explanation:

1 g = 100 cg

----------------------------------------------------------

Given

7.13 g = ? cg

Solve

7.13 × 100 = 713 cg

Hope this helps!! :)

Please let me know if you have any questions

6 0

2 years ago

Find the sum of the first 8 terms in the sequence 2 8 32 128

Zigmanuir [339]

the sequence is in multiples of 4 (2*4=8, 8*4=32, 32*4=128)

so 128*4=512, 512*4=2048, 2048*4=8192 & 8192*4=32768

2+8+32+128+512+2048+8192+32768=43690

4 0

2 years ago

Please explain how they plugged the removable discontinuity in this question.

kondor19780726 [428]

In the limit

$\displaystyle \lim_{x\to c} f(x)$

we're interested in the value that $f(x)$ converges to as $x$ gets closer to $c$ . So in fact $x\neq c$ .

In the given example, $f(x)$ is factorized to reveal a common factor of $x-1$ in the numerator and denominator. We have $x\neq1$ if $x\to1$ , so $x-1\neq0$ so we can simplify

$\dfrac{x-1}{x-1} = 1$

and *remove* the discontinuity.

Then

$\displaystyle \lim_{x\to1} \frac{2(x-1)}{(x+1)(x-1)} = \lim_{x\to1} \frac2{x+1} = \frac2{1+1} = 1$

8 0

1 year ago