(128 oz) * (2 oranges)/(5 oz) * (1 bag)/(11.5 oranges) * $3.49/bag ≈ $15.54
Note that we have assumed 11.5 oranges per bag, and that partial bags are available.
If Chantal must buy whole bags of oranges, 5 bags will be needed and the cost will be $17.45.
This bisector created a 90 degree angle
Remark
You must use the sin law to find this.

Multiply through by 12
12 *
*12

0.5269 = sin(x)
Now you have to use the inverse of the sine function.
Use your calculator for that
2nd F
sin-1
(0.5269)
= 31.79 degrees. <<<<<< Answer.
There sometimes is a second answer. I don't think there is in this case.
Answer: 
Step-by-step explanation:
We can use the Rational Root Test.
Given a polynomial in the form:

Where:
- The coefficients are integers.
-
is the leading coeffcient (
)
-
is the constant term 
Every rational root of the polynomial is in the form:

For the case of the given polynomial:

We can observe that:
- Its constant term is 6, with factors 1, 2 and 3.
- Its leading coefficient is 2, with factors 1 and 2.
Then, by Rational Roots Test we get the possible rational roots of this polynomial:

His budget is $5000
you take 800 and divide it by 0.16
gives you 5000