Question

What is an equation of the line that passes through the points (3, 0) and (6, -1)

Answer 1

Answer:

(Note: This is assuming that the answer can be in any format.)

$y - 0 = -\frac{1}{3} (x - 3)$

Step-by-step explanation:

When given at least two points, you can find write an equation using the point-slope formula: $y - y_1 = m (x - x_1)$. The $x_1$ and $y_1$ are the x and y values from one point that need to be substituted in to make an equation, as well as the $m$ which represents the slope.

Find the slope by using the slope formula $\frac{y_2 - y_1}{x_2 - x_1}$ and the two points given:

$\frac{-1-0}{6-3}$

$\frac{-1}{3}$

So, the slope is $-\frac{1}{3}$.

Next, choose a point (in this case, I chose (3,0)) and substitute its x and y values into $x_1$ and $y_1$ respectively, and also substitute  $-\frac{1}{3}$ for m. This forms an equation of a line in point-slope formula:

$y - 0 = -\frac{1}{3} (x - 3)$

Answer 2

Y= -1/3x + 1

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