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mylen [45]
3 years ago
5

Help pls I need it badly​

Mathematics
1 answer:
photoshop1234 [79]3 years ago
6 0

9514 1404 393

Answer:

  22

Step-by-step explanation:

For calculators without a cube root key, you can use the 1/3 power. The attached shows the quotient to be about 22.

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Ann borrowed $6000 from the bank for 5 years at 12% rate. How much does she owe the bank? I need your help PLEASE!!!
marysya [2.9K]

Answer:

Anna owes $3600 to the bank

Step-by-step explanation:

12/100 * 6000 = 720 * 5 years

= $3600

Hence Anna owes $3600 to the bank

8 0
2 years ago
I’ll mark brainlest! pls help :(
Ilia_Sergeevich [38]

Answer:

square root: \sqrt{61}

decimal: 7.81

Step-by-step explanation:

8 0
4 years ago
Below are the solutions for a variable "x." State the solution that matches the graph below.
Aloiza [94]
We have a number line as indicated in the figure above. From this figure we know that the <em>x-values</em> <em>increase f</em><em>rom left to right</em>. So we need to write the solution<span> that matches the previous graph. Taking a look on the graph we see that x begins in -3 and closes in 8, that is, x <em>takes values from -3 to 8</em>. In a mathematical language this is given by the following statement: 

</span>x \in [-3,8]<span>


</span>
7 0
4 years ago
Eight more than four times a number is negative twelve
quester [9]
The equation is 4x+8=-12 so you subtract 8 from both sides to give you 4x=-20, then you divide by 4 to get x=-5
4 0
4 years ago
Point R is at (2, 1.2) and Point T is at (2, 2.5) on a coordinate grid. The distance between the two points is
Sergeu [11.5K]
<h3>Answer:   1.3</h3>

========================================

Work Shown:

The two points we have are (x_1,y_1) = (2,1.2) and (x_2,y_2) = (2,2.5)

Apply the distance formula

d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\\\d = \sqrt{(2-2)^2+(1.2-2.5)^2}\\\\d = \sqrt{(0)^2+(-1.3)^2}\\\\d = \sqrt{0+1.69}\\\\d = \sqrt{1.69}\\\\d = 1.3\\\\

-------------------------

A shortcut is possible by subtracting the y coordinates of the two points, and making the result positive through the use of absolute value.

So we either say

|y1-y2| = |1.2-2.5| = |-1.3| = 1.3

or,

|y2 - y1| = |2.5 - 1.2| = |1.3| = 1.3

We get the same result. This shortcut is valid because the x coordinates of both points are the same.

5 0
3 years ago
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