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Andreas93 [3]
2 years ago
14

Tina has eight packs of paper each of her packs contain 50 sheets. Caz has three packs of paper each of his packs contain 125 sh

eets. Juan has 350 sheets of paper which statement is true
Mathematics
1 answer:
Vesna [10]2 years ago
7 0

Answer:

i think the question is incomplete but

Tina at an average contains each package of

50 sheets ÷ 8 pack

6.205 of sheet in each pack

125 sheets ÷ 3 packs

caz contain at average 41.60 sheet average

but where the juan packs of paper that's why question is incomplete

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BC =<br> Round your answer to the nearest hundredth.<br> B<br> 50°<br> 7
Brrunno [24]

Answer:

BC = 5.87

Step-by-step explanation:

Reference angle = 50°

Side Opposite to reference angle = 7

Adjacent side = BC = ?

Apply trigonometric function, TOA, thus:

Tan 50 = Opp/Adj

Tan 50 = 7/BC

BC × Tan 50 = 7

BC = 7/Tan 50

BC = 5.87369742 ≈ 5.87 (nearest hundredth)

4 0
3 years ago
Parvinis older than Jan, who is
MatroZZZ [7]

Using the arrangements formula, it is found that there are 24 ways for them to stand in line so that the youngest person is always first, and the oldest person is always last.

<h3>What is the arrangements formula?</h3>

The number of possible arrangements of n elements is given by the factorial of n, that is:

A_n = n!

In this problem, we have that there are 6 people. The youngest person(Leslie) has to be first, while the oldest(Parvinis) has to be last, while the remaining 4 can be arranged, hence the number of ways for them to stand in line is given by:

A_4 = 4! = 24

More can be learned about the arrangements formula at brainly.com/question/24648661

#SPJ1

8 0
2 years ago
I need help please can someone help me !!!!!!
Valentin [98]
What are you trying to find? Area, Volume, Circumference, or perimeter?
7 0
3 years ago
When obtaining a confidence interval for a population mean in the case of a finite population of size N and a sample size n whic
Elanso [62]

Answer:

95% Confidence interval for the mean

142.8 \leq\mu\leq158.4

Step-by-step explanation:

We have to calculate a 95% confidence interval for the mean of a finite population.

The error is multiplied by the following finite population correction factor:

cf=\sqrt{\frac{N-n}{N-1} }

The standard deviation can be estimated as

\sigma=\frac{s}{\sqrt{n}} \sqrt{\frac{N-n}{N-1} } =\frac{24.4}{\sqrt{32} }* \sqrt{\frac{200-32}{200-1} }=3.963

The 95% confidence interval has a z value of 1.96, so it becomes:

M-z*\sigma_c\leq\mu\leq M+z*\sigma_c\\\\150.6-1.96*3.963\leq\mu\leq 150.6+1.96*3.963\\\\ 142.8 \leq\mu\leq 158.4

5 0
3 years ago
My teacher needs an estimate, may someone help me?​
castortr0y [4]
Answer; 8.75
Explanation;
Hope this helps
8 0
3 years ago
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