Answer:
Step-by-step explanation:
Answer:
45 minutes
Step-by-step explanation:
At 30 mph for 1/4 hour, Peter has a 7.5 mile head start. After he leaves, Mitchell closes that gap at the rate of 40-30 = 10 miles per hour. It will take him ...
t = d/s
t = (7.5 mi)/(10 mi/h) = 0.75 h
to catch Peter.
Mitchell will catch Peter in 45 minutes.
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<em>Alternate Solution</em>
Another way to look at it is that Mitchell's 10 mph advantage is 1/3 of Peter's speed, so it will take 1/(1/3) = 3 times the period of Peter's head start:
3 × 15 minutes = 45 minutes . . . for Mitchell to catch Peter
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You can write equations involving time and distance and see where the distances traveled become the same. You need to be careful choosing the time reference, since you're concerned with Mitchell's travel time. I personally prefer to work "head start" problems by considering the differences in time and speed, as above. This is where you end up using the equations approach, anyway.
means that the triangles are congruent, that is exactly identical.
The order of letters is very important. Form the given congruence we can write the following ratio:
(notice that we do not mix the order: the first 2 letters of VWX are compared to the first 2 letters of KLJ and so on)
the ratio is one because the corresponding sides are equal.
Answer: 5 units
Answer:
Hello your question is incomplete attached below is the correct question
and the solution
answer: A
Step-by-step explanation:
attached below is a detailed solution of the given problem
There exists P and C such that ( ∵ λ1 ≠ λ21 so A is diagonalizable )
