All categories

3 years ago

Lol it looks easy but everytime i submit my answer it ends up wrong sooo help pls

Mathematics

2 answers:

gregori [183]3 years ago

8 0

Answer:

(y+8)(y+2)

Step-by-step explanation:

y^2 + 10y + 16

What two numbers multiply to 16 and add to 10

8*2 = 16

8+2 =10

(y+8)(y+2)

Alex777 [14]3 years ago

4 0

Y^2+10y+16
y^2+8y+2y+16
y(y+8)+2(y+8)
(y+8)(y+2)

You might be interested in

The diameter of a circular tablecloth is 72 inches. Find the area and circumference. Use 3.14 as an approximation for pi.

nalin [4]

Answer:

Part 1) The area is $A=4,069.44\ in^{2}$

Part 2) The circumference is $C=226.08\ in$

Step-by-step explanation:

step 1

Find the area

we know that

The area of a circle (circular tablecloth) is equal to

$A=\pi r^{2}$

we have

$r=72/2=36\ in$ ------> the radius is half the diameter

$\pi =3.14$

substitute

$A=(3.14)(36)^{2}$

$A=4,069.44\ in^{2}$

step 2

Find the circumference

we know that

The circumference of a circle (circular tablecloth) is equal to

$C=\pi D$

we have

$D=72\ in$

$\pi =3.14$

substitute

$C=(3.14)(72)$

$C=226.08\ in$

5 0

3 years ago

What is the area of a circle. Using 3.14 for. A circle with diameter of 8.4 ft.

ira [324]

Hey there! I'm happy to help!

First, let's find the radius. The radius is half of the diameter.

8.4/2=4.2

Here's how to find the area of a circle.

Square the radius.

4.2²=17.64

And multiply by pi (3.14 in our case)

17.64(3.14)=55.3896

We round to the nearest tenth, giving us an area of 55.4 ft²

Have a wonderful day! :D

5 0

3 years ago

Gloria bought each of her three younger siblings a movie ticket.find the total cost of the movie tickets if each ticket cost $9.

jeka94

Answer:

The answer is 29.25

Step-by-step explanation:

Using distributive property, the equation would be 3(9.75).

9.75*1+9.75*1+9.75*1=29.25

4 0

3 years ago

Please help and leave explanation

chubhunter [2.5K]

Answer: x = 150°

Step-by-step explanation:

The tangent intersects the circle's radius at a 90° angle, so ∠OAC = ∠OBC = 90°.

AOBC is a quadrilateral and we know that sum of interior angles of quadrilateral equals to 360°.

Now,

∠OAC + ∠OBC + ∠AOB + ∠ACB = 360°

90° + 90° + x + 30° = 360°

210° + x = 360°

x = 360° - 210°

x = 150°

7 0

3 years ago

Two teams A and B play a series of games until one team wins three games. We assume that the games are played independently and

Olenka [21]

Answer:

The probability that the series lasts exactly four games is $3p(1-p)(p^{2} + (1 - p)^{2})$

Step-by-step explanation:

For each game, there are only two possible outcomes. Either team A wins, or team A loses. Games are played independently. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

We also need to know a small concept of independent events.

Independent events:

If two events, A and B, are independent, we have that:

$P(A \cap B) = P(A)*P(B)$

What is the probability that the series lasts exactly four games?

This happens if A wins in 4 games of B wins in 4 games.

Probability of A winning in exactly four games:

In the first two games, A must win 2 of them. Also, A must win the fourth game. So, two independent events:

Event A: A wins two of the first three games.

Event B: A wins the fourth game.

P(A):

A wins any game with probability p. 3 games, so n = 3. We have to find P(A) = P(X = 2).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(A) = P(X = 2) = C_{3,2}.p^{2}.(1-p)^{1} = 3p^{2}(1-p)$

P(B):

The probability that A wins any game is p, so P(B) = p.

Probability that A wins in 4:

A and B are independent, so:

$P(A4) = P(A)*P(B) = 3p^{2}(1-p)*p = 3p^{3}(1-p)$

Probability of B winning in exactly four games:

In the first three games, A must win one and B must win 2. The fourth game must be won by 2. So

Event A: A wins one of the first three.

Event B: B wins the fourth game.

P(A)

P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(A) = P(X = 1) = C_{3,1}.p^{1}.(1-p)^{2} = 3p(1-p)^{2}$

P(B)

B wins each game with probability 1 - p, do P(B) = 1 - p.

Probability that B wins in 4:

A and B are independent, so:

$P(B4) = P(A)*P(B) = 3p(1-p)^{2}*(1-p) = 3p(1-p)^{3}$

Probability that the series lasts exactly four games:

$p = P(A4) + P(B4) = 3p^{3}(1-p) + 3p(1-p)^{3} = 3p(1-p)(p^{2} + (1 - p)^{2})$

The probability that the series lasts exactly four games is $3p(1-p)(p^{2} + (1 - p)^{2})$

8 0

3 years ago