D=4n-2, d+2=4n-2+2, d+2=4n
(d+2)/4=(4n)/4, 1/4d+1/2=n
n=1/4n+1/2
size 3=
n=1/4*3/1=3/4, 3/4+1/2=5/4=1 1/4
size 3=1 1/4
size 6=
n=1/4*6/1=6/4, 6/4+1/2=8/4=2
size 6=2
size 10=
n=1/4*10/1=10/4, 10/4+1/2=12/4=3
size 10=3
Determine the mode(s) of the data 2, 2, 2,3,5,5, 6, 7, 8, 8, 8, 9, 10.
Genrish500 [490]
To find the mode, put all the numbers in order from least to greatest, then count how many times you see a number. The number you see the most is the mode. In this problem, we have more than one mode, we have two. The number two appears three times and so does number eight. Having two modes is called bimodal, and having more than two modes is called multimodal. So we have a bimodal of two and eight from this data.
4x=-3y+17 becomes 4x+3y=17
4x+3y=17
3x-4y=-6
alrighty
elimination
muliply first equation by 4 and 2nd by 3 and add them
16x+12y=68
9x-12y=-18
add them
25x+0y=50
25x=50
idivide both sides by 25
x=2
sub back
3x-4y=-6
3(2)-4y=-6
6-4y=-6
-4y=-12
y=3
(x,y)
(2,3)
The fourth term in the arithmetic sequence is 4. This is because you are subtracting 3 each time, and you already have your first three numbers in the pattern, so all you have to do is subtract another 3 in order to get 4.
