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Vedmedyk [2.9K]
3 years ago
12

Tess rolls 2 fair dice. What is the probability of obtaining two 4's?

Mathematics
2 answers:
harina [27]3 years ago
4 0

Answer:

1/36

Step-by-step explanation:

Since Tess rolled 2 different dices, there are 36 different possibilities. Rolling two 4's is 1 of them.

Therefore, the probability of Tess rolling 2 fair dice is 1/36

Hope this helped have a great rest of your day!

anygoal [31]3 years ago
3 0

Answer:

1 out of 36 chance because add what a dice equals to then divide

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PLEASE HELP 15 points!! Todd has created the following diagram to prove the Pythagorean theorem. He drew right ABC with leg leng
masya89 [10]

Answer:

c^2 = a^2 + b^2. Hope this helps!

7 0
3 years ago
Read 2 more answers
6.6666 to the thousands
salantis [7]
6.6666 rounded to the nearest thousandth is 6.667.
The number in the ten thousandths place is greater than five, so the 6 in the thousandths place rounds up to a seven
8 0
3 years ago
How do you round 126,009 to its nearest hundred thousand nearest ten thousand and nearest thousand
harina [27]

Answer:

-

Step-by-step explanation:

Rule for rounding :

You look at the number next to the place value you are meant to round and if the number is :

=

4 and below you round down.

5 and above you round up

Nearest hundred thousand: 100,000

This is because you look at the number next to the hundred thousand spot which is a 2 so you round down

Nearest ten thousand: 130,000

Same reason as before the number next to the 2 in the number is a 6. So you round up

Nearest thousand: 126,000

The number next to the thousandth place value is a 0 so you round down

3 0
3 years ago
4. The population of Bay Village is 35,000 today. Every year the
frosja888 [35]

Answer:

Linear Model:   y(x)=35,000+750x

Step-by-step explanation:

In principle <em>Linear Models </em>are employed when we want to define a relationship between an independent and a dependent variable. <em>Linear Models</em> are also known as<em> Functions </em>, where one variable is expressed as a function of <em>at least one</em> other variable. The most common example would be a dependent variable y that is directly linked as a response to any changes of an independent variable x. The most common expression of such relationship would be y=ax where a is the relationship factor between y and x and is also known as the <em>slope </em>of the function (representing a rate of change of that function).

In this question we are told that the population of Bay Village today is 35,000. So we know this is our constant variable, lets call it  b.

Next we know that every year the population is increased by 750 people. So we know that our variable and thus our independent variable is every year which we shall call x and our fixed factor is the 750 increment which we will call a.  

From that we can conclude that:

<em>Year 1 Population: 35,000</em>

<em>Year 2 Population: 35,000 + 750 = 35,750</em>

<em>Year 3 Population: 35,750 + 750 = 36,500 </em>

And so on and so forth.<em> </em>

So we want to express the above as a Linear Model of the form:

<em> y = ax + b   </em>Eqn(1).

Thus from Eqn (1) and all information given (i.e. pluging in values) we finally obtain:

y(x)=35,000+750x

Which for every different value of  x (i.e. every year) we can obtain the new and increased population  y(x).

7 0
3 years ago
5a+5b+5c=-20<br> 4a+3b+3c=-6<br> -4a+3b+3c=9
tekilochka [14]
For 5a+5b+5c=-20

A= -4 - b - c

B= -4 - a - c

C= -4 - a - b

———————————

4a+3b+3c=-6

A= -3/2 - 3b/4 - 3c/4

B= -2 - 4a/3 - c

C= -2 - 4a/3 - b

———————————

-4a+3b+3c=9

A= -9/4 + 3b/4 + 3c/4

B= 3 + 4a/3 - c

C= 3 + 4a/3 - b
4 0
3 years ago
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