X³ - 9x² + 5x - 45
x²(x - 9) - 5(x - 9) ⇒ x³ - 9x² - 5x + 45 INCORRECT
x²(x + 9) - 5(x + 9) ⇒ x³ + 9x² - 5x - 45 INCORRECT
x(x² + 5) - 9(x² + 5) ⇒ x³ + 5x - 9x² - 45 CORRECT
It just needs to be rearranged.
x(x² - 5) - 9(x² - 5) ⇒ x³ - 5x - 9x² + 45 INCORRECT
Answer:
5.5%
Step-by-step explanation:
1.54/28=0.055
Answer:
q<392
Step-by-step explanation:
First, we turn words into an inequality. Then, we solve for q.
![\frac{q}{14}](https://tex.z-dn.net/?f=%5Cfrac%7Bq%7D%7B14%7D%20%3C28%5C%5Cq%3C28%2A14%5C%5Cq%3C392)
It is also a good idea to check our answer, to make sure it is reasonable and we did not make a careless mistake.
![3](https://tex.z-dn.net/?f=3%3C392%5C%5C%5Cfrac%7B3%7D%7B14%7D%20%3C28)
The value satisfies the equation, so this should be correct.
1) ![y=-0.5x-2](https://tex.z-dn.net/?f=y%3D-0.5x-2)
The graph of the above equation is attached in the attachment below.
For all the values from negative infinity to -4, the function is positive.
X ∈ (-∞,-4]
2) ![y=-1.5x+3](https://tex.z-dn.net/?f=y%3D-1.5x%2B3)
To find the x- intercept, plug y =0
![0=-1.5x+3](https://tex.z-dn.net/?f=0%3D-1.5x%2B3)
![1.5x=3](https://tex.z-dn.net/?f=1.5x%3D3)
![x=2](https://tex.z-dn.net/?f=x%3D2)
x intercept = (2,0)
To find the y- intercept, plug x=0
![y=-1.5(0)+3](https://tex.z-dn.net/?f=y%3D-1.5%280%29%2B3)
![y=3](https://tex.z-dn.net/?f=y%3D3)
Y- intercept = ( 0,3)
3) ![y=13-x](https://tex.z-dn.net/?f=y%3D13-x)
Y- intercept = (0,13)
x- intercept = (13,0)
Area of triangle = ![\frac{bh}{2}](https://tex.z-dn.net/?f=%5Cfrac%7Bbh%7D%7B2%7D)
Area of triangle = ![\frac{13\times13}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B13%5Ctimes13%7D%7B2%7D)
Area =
sq unit.
4) The graphs of
and
is attached in the attachment below.
The intersection point is ( 5,-3)
5) A = (-3,0)
B = (4,5)
C = (0,-4)
Slope of AB = ![\frac{5-0)}{4-(-3)} =\frac{5}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B5-0%29%7D%7B4-%28-3%29%7D%20%3D%5Cfrac%7B5%7D%7B7%7D)
Slope intercept of line ![y=mx+b](https://tex.z-dn.net/?f=y%3Dmx%2Bb)
Where, m is the slope and b is the y- intercept.
Plugging point A and the slope in the y- intercept to find the value of b.
![0=\frac{5(-3)}{7} +b](https://tex.z-dn.net/?f=0%3D%5Cfrac%7B5%28-3%29%7D%7B7%7D%20%2Bb)
![b=\frac{15}{7}](https://tex.z-dn.net/?f=b%3D%5Cfrac%7B15%7D%7B7%7D)
Equation of line AB: ![y=\frac{5x}{7} +\frac{15}{7}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B5x%7D%7B7%7D%20%2B%5Cfrac%7B15%7D%7B7%7D)
Slope of BC = ![\frac{-4-5}{0-4} =\frac{9}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B-4-5%7D%7B0-4%7D%20%3D%5Cfrac%7B9%7D%7B4%7D)
Plug C = (0,-4)
![-4=0+b](https://tex.z-dn.net/?f=-4%3D0%2Bb)
b=-4
equation of line BC= ![y=\frac{9x}{4} -4](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B9x%7D%7B4%7D%20-4)
Slope of line AC = ![\frac{-4-0}{0--3} =\frac{-4}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B-4-0%7D%7B0--3%7D%20%3D%5Cfrac%7B-4%7D%7B3%7D)
Equation of line AC = ![y=\frac{-4x}{3} -4](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B-4x%7D%7B3%7D%20-4)
Y intercept of AB = ![(0,\frac{15}{7} )](https://tex.z-dn.net/?f=%280%2C%5Cfrac%7B15%7D%7B7%7D%20%29)
If d₁ and d₂ are the lengths of the diagonals, the area is given by
.. A = (1/2)*d₁*d₂
.. A = (1/2)*(12 in)*(16 in)
.. A = 96 in²
If b is the base and h is the height, the area is given by
.. A = b*h
We know the values of A and b, so
.. 96 in² = (10 in)*h
.. (96 in²)/(10 in) = h = 9.6 in
The height is 9.6 in.