Write an equation. To do this, make one integer equal to x, and the other equal to x+1. Set these equal to 149. Your equation should read x+(x+1)=149. Solve. To do this, add the two x's together. Your equation is now 2x+1=149. Get your x's alone. First, subtract 1 from both sides. Now the equation is 148=2x. Divide both sides by 2 to get x alone. You now have x=74. Plug this value back into the original equation to find your value for the other integer, and you have the two integers as 74 and 75. Hope this helps!
5(3 +x) – 2 = (5+3)*(5+x)
(8-2)*(5x-2)
6*5x-2
this Is what I came up with.
Recall your d = rt, distance = rate * time
one car is going at 55kph, at say hmmm "t" time
the second car zooms by at 75kph, an hour later, thus " t + 1 "
notice, overtaking the 1st car, simply means, the second car comes from behind approaches the first car from behind and "gets there", at that very second, both cars have travelled a distance, say "d"
if the first car travelled "d" kilometers
for the second car to "get there" has to had travelled "d" distance as well

solve for "t"
X=9
Y=2 i think it’s the answer