Answer:
14 cupcakes per hour
Step-by-step explanation:3 1/2 or 3.5 times 4
Answer:
<h3>A) 204m</h3><h3>B) 188m</h3>
Step-by-step explanation:
Given the rocket's height above the surface of the lake given by the function h(t) = -16t^2 + 96t + 60
The velocity of the rocket at its maximum height is zero
v = dh/dt = -32t + 96t
At the maximum height, v = 0
0 = -32t + 96t
32t = 96
t = 96/32
t = 3secs
Substitute t = 3 into the modeled function to get the maximum height
h(3) = -16(3)^2 + 96(3) + 60
h(3) = -16(9)+ 288 + 60
h(3) = -144+ 288 + 60
h(3) = 144 + 60
h(3) = 204
Hence the maximum height reached by the rocket is 204m
Get the height after 2 secs
h(t) = -16t^2 + 96t + 60
when t = 2
h(2) = -16(2)^2 + 96(2) + 60
h(2) = -64+ 192+ 60
h(2) = -4 + 192
h(2) = 188m
Hence the height of the rocket after 2 secs is 188m
Answer:
1. c 2. a 3. b
Step-by-step explanation:
The best way to prove these results are the right ones is by multiplying diagonally :
1. 1/3 = 4/12 -----> 1 . 12 = 12 ; 3 . 4 =12
2. 1/2 = 3/6 ------> 1 . 6 = 6 ; 2 . 3 = 6
3. 2/5 = 6/15 -----> 2 . 15 = 30 ; 5 . 6 = 30
The results of the multiplications must be the same if the fractions are equivalent.
26 maybe it can be ım not sure
Answer: w=12, y=6√3
Step-by-step explanation:
Looking at the figure, we can split the triangle into 2 separate triangles. One on the left and one on the left. The triangle on the right is a 30-60-90 triangle. For this triangle, the hypotenuse is 2x in length. This is directly opposite of the right angle. The leg opposite to 30° is x in length. The leg opposite 60° is x√3 in length. Once you know the length of one side, you can plug in x to find the length of the other legs.
In this case, w and y are located on the same 30-60-90 triangle. Normally we would focus on that triangle to find our values, but in this instance, we don't have any values. We have to use the left triangle to find the leg that both triangles share.
The left triangle is a 45-45-90 triangle. For this triangle, the legs opposite of 45° is x in length. The hypotenuse is x√2. Since we know the hypotenuse, we can use it to find x.
x√2=8
x=8/√2
x=5.7 or 6 [Let's use 6 so that it is easier to work with a whole number]
Now that we know x, we can find w and y. Going back to the right triangle, we know the hypotenuse is 2x. We plug in 6 to find the length.
w=2x
w=2(6)
w=12
We know the leg opposite of 60° is x√3. We can plug in x.
y=6√3
