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nordsb [41]
3 years ago
12

At the moment a certain medicine is injected, its concentration in the bloodstream is 120 milligrams per liter. From that moment

forward, the medicine's concentration drops by 30% percent each hour. Write a function that gives the medicine's concentration in milligrams per liter, C(t), t hours after the medicine was injected. If anyone responds, thank you <3
Mathematics
1 answer:
notka56 [123]3 years ago
5 0

Answer: C(t) = 120(1-0.30)^t

Step-by-step explanation:

Exponential equation for decay:y= A(1-r)^t, where A = initial value, r= decay rate , t= time.

As per given, A = 120ml , r= 0.30

C(t) = 120(1-0.30)^t

Hence, the required function that gives the medicine's concentration in milligrams per liter, C(t), t hours after the medicine was injected.

C(t) = 120(1-0.30)^t

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How many solutions does this equation have? 6x-2=6x+7
Anon25 [30]

None, the equation 6x - 2 = 6x + 7 does not have any solutions.

<h3>What is an algebraic equation? </h3>

An algebraic equation is an equation that consists of numbers and variables. To solve the variables, there is a need to make use of some or all of the arithmetic operations such as:

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From the given equation:

6x - 2 = 6x + 7

Collect like terms

6x - 6x -2 - 7 = 0

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Since there is no variable to solve for in the equation, we can conclude that the equation does not have any solutions.

Learn more about algebraic equations here:

brainly.com/question/4344214

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3 years ago
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Pasha works as a food scientist. He designed a recipe for crackers that are 40% wheat flour by weight. He made a test batch of t
MA_775_DIABLO [31]
To answer this question, you need to find 40% of 1 1/2. To find a percentage of a value, you can divide the percentage by 100 and multiply that by the total.

In this situation, 40 / 100 = 0.4
So 1 1/2 x 0.4 = 0.6

Pasha will use 0.6 pounds of wheat flour in the test batch.
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4 years ago
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Write the Taylor Series for f(x) = sin (x)center<br> 4x^4+3x^3+2x^2 x 8 centered at a 2
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Step-by-step explanation:

8 0
3 years ago
A team can row 40 km in 2 hours when rowing with the current, but only
dexar [7]
<h3>Answer:  14 km per hour</h3>

=====================================================

Work Shown:

x = rowing speed when there is no current

c = speed of the current

speeds are in km per hour

-----------

Going downstream, i.e. with the current:

x+c = faster speed since the current is pushing you

distance = rate*time

d = r*t

40 = (x+c)*2

x+c = 40/2

x+c = 20

c = 20-x

-----------

Going upstream, i.e. against the current:

x-c = slower speed since the current is working against you

d = r*t

16 = (x-c)*2

16 = 2x-2c

2x-2c = 16

2(x-c) = 16

x-c = 16/2

x-c = 8

x-(20-x) = 8 ... plug in c = 20-x

x-20+x = 8

2x-20 = 8

2x = 8+20

2x = 28

x = 28/2

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3 0
2 years ago
In a certain Algebra 2 class of 30 students, 14 of them play basketball and 10 of them play baseball. There are 14 students who
Veseljchak [2.6K]

Answer:

In a certain Algebra 2 class of 30 students, 22 of them play basketball and 18 of them play baseball. There are 3 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

I know how to calculate the probability of students play both basketball and baseball which is 1330 because 22+18+3=43 and 43−30 will give you the number of students plays both sports.

But how would you find the probability using the formula P(A∩B)=P(A)×p(B)?

Thank you for all of the help.

That formula only works if events A (play basketball) and B (play baseball) are independent, but they are not in this case, since out of the 18 players that play baseball, 13 play basketball, and hence P(A|B)=1318<2230=P(A) (in other words: one who plays basketball is less likely to play basketball as well in comparison to someone who does not play baseball, i.e. playing baseball and playing basketball are negatively (or inversely) correlated)

So: the two events are not independent, and so that formula doesn't work.

Fortunately, a formula that does work (always!) is:

P(A∪B)=P(A)+P(B)−P(A∩B)

Hence:

P(A∩B)=P(A)+P(B)−P(A∪B)=2230+1830−2730=1330

7 0
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