Answer:
C. the initial number of club members, in hundreds
Step-by-step explanation:
The general form of such an expression is ...
(initial value)×(growth factor per period)^(number of periods)
The use of 12 in the exponent suggests that the growth factor of 1.02 is an annual factor. If that is the case, for t months, the membership should be modeled as ...
1.8(1.02^(t/12))
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As written, the expression is not an exponential expression. With appropriate parentheses, it might be a good model if t is the number of <em>years</em> (not <em>months</em>), and if the expected growth rate is 2% per month.
1.8(1.02^(12t))
Answer:
2
Step-by-step explanation:
In this case, you have to substitute the w for -1, and then do the operation:
-6( -1 )^2 + 13( -1 ) + 21
-6( 1 ) - 13 +21
-6 -13 + 21
-19 + 21
2
Can you take a picture of the whole problem? i may be able to solve it then. Thanks!
The answer choices are sufficiently far apart that you can work this backward. The sum will be ...
236,196*(1 + 1/3 + 1/9 + 1/27 + ...)
so a reasonable estimate can be given by an infinite series with a common ratio of 1/3. That sum is
236,196*(1/(1 - 1/3)) = 236,196*(3/2)
Without doing any detailed calculation, you know the best answer choice is ...
354,292
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There are log(236196/4)/log(3) + 1 = 11 terms* in the series, so the sum will be found to be 4(3^11 -1)/(3-1) = 2*(3^11-1) = 354,292.
Using the above approach (working backward from the last term), the sum will be 236,196*(1-(1/3)^11)/(1-(1/3)) = 236,196*1.49999153246 = 354,292
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* If you just compute log(236196/4)/log(3) = 10 terms, then your sum comes out 118,096--a tempting choice. However, you must realize that the last term is larger than this, so this will not be the sum. (In fact, the sum is this value added to the last term.)
Answer:
2r - 15
Step-by-step explanation:
product of 2 and r is 2r and then minus by 15. im sorry if this is wrong haha
