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3 years ago

5

A color printer prints 8 pages in 5 minutes. How many minutes does it take per page?

1 answer:

sveta [45]3 years ago

8 0

Answer:

It takes 5/8 minutes or 0.625 minutes to print per page.

Step-by-step explanation:

The find the singular unit value of how long it would take per page you simply divide the amount that you are trying to figure out by the total amount of time you are taking and in this case it would be 5 divided by 8 in order to solve for the amount of minutes it takes per page.

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Is y = 3/2x +5/4 and -2x+8y=-25 a solution

nekit [7.7K]

Answer: x=-35/10

y=-4

Step-by-step explanation:

y = 3/2x +5/4

-2x+8y=-25

--------------------

replace y in second equation with: y = 3/2x +5/4

-2x+8(3/2x+5/4)= -25

-2x+12x+10= -25

10x=-35

x=-35/10

x=-3.5

7+8y= -25

8y=-32

y=-4

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3 years ago

What is the approximate length of minor arc XZ

Yakvenalex [24]

Answer:

3.7

Step-by-step explanation:

2r(pi)(∅/360)

2*3*(pi)*(70/360)

6*(pi)*(0.19444...)

3.665191429188092

3.7

3 0

4 years ago

What is the solution to 4 x + 6 less-than-or-equal-to 18? x less-than-or-equal-to 3 x less-than-or-equal-to 6 x less-than-or-equ

Nana76 [90]

Answer:

x-less than-or-equal-to 3

Step-by-step explanation:

4x + 6 < 18 (less than or equal to)

4x < 12 (less than or equal to) x < 3 (less than or equal to)

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3 years ago

Read 2 more answers

Please help solve for angles Q X and Z

Iteru [2.4K]

Answer:

125

Step-by-step explanation:

Sum of Exterior Angles must add to 360 so

$60 + 70 + 40 + 65 + x = 360$

$235 + x = 360$

$x = 125$

6 0

3 years ago

From a practice assignment:<br>solve the following differential equation given initial conditions

hodyreva [135]

If $y' = e^y \sin(x)$ and $y(-\pi)=0$ , separate variables in the differential equation to get

$e^{-y} \, dy = \sin(x) \, dx$

Integrate both sides:

$\displaystyle \int e^{-y} \, dy = \int \sin(x) \, dx \implies -e^{-y} = -\cos(x) + C$

Use the initial condition to solve for $C$ :

$-e^{-0} = -\cos(-\pi) + C \implies -1 = 1 + C \implies C = -2$

Then the particular solution to the initial value problem is

$-e^{-y} = -\cos(x) - 2 \implies e^{-y} = \cos(x) + 2$

(A)

4 0

2 years ago