All categories

2 years ago

Can someone please help

Mathematics

1 answer:

navik [9.2K]2 years ago

3 0

C because 45.1%=45% so 45% is closest to -3 to 0 degress

Why did you delete my answer?

You might be interested in

Which of the following equations has a solution that is negative?

drek231 [11]

Answer:

b. – 0.4(x + 1.6) = 1.6

Step-by-step explanation:

3 0

2 years ago

translate this into an expression: the quotient of a number, x, and 8, could you please explain it to me?

Xelga [282]

Answer:

x/8

Step-by-step explanation:

First, we are given "the quotient of...". This means that we are dividing something/something else. If two numbers are given in the phrase "something and something else", the first number given will be the something, and the second number will be the something else.

The first number listed is x. Therefore, we have

x/something else.

Next, we are given "and 8", so we have x/8 as our expression

3 0

3 years ago

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth. 5y2 − 8y = 2 11.2, –9.6 0.22, –1.

Vesna [10]

Answer:

Y= 1.82, –0.22

Step-by-step explanation:

8 0

3 years ago

Expan and simplify (x+3) (x+5)

just olya [345]

Answer:

x= 3, x=5 or x^2 + 8x + 15

Step-by-step explanation:

(x+3)(x+5)

(x*x)(x*5)(3*x)(3*5)

x^2 + 5x + 3x + 15

x^2 + 8x + 15

x+3 = 0 x+5 = 0

-3 -3 -5 -5

x= -3 x= -5

8 0

3 years ago

Read 2 more answers

In order to help identify baby growth patterns that are unusual, we need to construct a confidence interval of the mean head cir

sukhopar [10]

Answer:

The 99% confidence interval estimate of the mean head circumference of all 2-month-old babies is (40.18cm, 41.02cm).

Step-by-step explanation:

Our sample size is 100.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 100-1 = 99$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-\alpha}{2} = \frac{0.01}{2} = 0.005$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 99 and 0.005 in the t-distribution table, we have $T = 2.626$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{1.6}{\sqrt{100}} = 0.16$

Now, we multiply T and s

$M = Ts = 2.626*0.16 = 0.42$

For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is

$L = 40.6 - 0.42 = 40.18$ cm

For the upper end of the interval, we add the sample mean and M. So the upper end of the interval here is

$L = 40.6 + 0.42 = 41.02$ cm

The 99% confidence interval estimate of the mean head circumference of all 2-month-old babies is (40.18cm, 41.02cm).

3 0

3 years ago