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ra1l [238]
3 years ago
6

GEOMETRY// Area? Also please provide an explanation(:

Mathematics
1 answer:
Zina [86]3 years ago
8 0

Answer:

A = 80

Step-by-step explanation:

B = 8

H = 10

Area of a Parallelogram = B x H = 8 x 10 = 80

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3(4-2) help please thank you
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Jamal makes $12.00/hour and worked 9 hours today. What is his total pay? Don't forget to calculate overtime pay.​
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An accounting firm is planning for the next tax preparation season. From last years returns, the firm collects a systematic rand
Elena L [17]

Answer:

a)From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard error for the mean would be:

\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14

b) We want this probability:

P(\bar X >120)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

P( z>2.143) = 1-P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Part a

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard error for the mean would be:

\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14

Part b

We want this probability:

P(\bar X >120)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

P( z>2.143) = 1-P(Z

4 0
3 years ago
How to write each fraction or mixed number as a decimal
4vir4ik [10]

okay lets foces on question 20. 3/20

all you need to do is times the dinominator into 100 so 20x5=100 and now you have to multipy the same number that you multiplyed the first one by so 3x5=15 so the anwer would be 15/100 and to put that in a decimal you need to see the number on top witch is 15 so your real ANWSER IS   .15

8 0
3 years ago
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