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2 years ago

How do I evaluate each using the values given

Mathematics

1 answer:

mrs_skeptik [129]2 years ago

6 0

Answer:

Hello!!! Princess Sakura here ^^

Step-by-step explanation:

$(p)(m+m+m)\\(5)(1+1+1)\\(5)(3)\\15$

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PLEASE HELP ASAP PLEASE PLEASE PLEASE

vovikov84 [41]

Answer:

First blank- 4x

Second blank- combine

Third blank- X

Hope this helps :3

(Write feedback if incorrect)

6 0

2 years ago

____ 2. The set of numbers {9, 8, 7, …}

OverLord2011 [107]

Answer:

A. x > -4

Step-by-step explanation:

< less than

>greater than

the unknown number x is greater than -4

{9, 8, 7, ...} the number is counting down. So the next number is 6.

is 6 greater than -4

or less than -4

therefore

x(which is 6) is greater than -4

x > -4

6 0

2 years ago

What happens to the area of a circle when the radius is doubled? (1 point) it is doubled?

Alina [70]

I think the circle would grow bigger into an oval.

7 0

2 years ago

I am between 24 and 34 . you say my name when you count by twos from zero. you say my name when you count by fives from zero. wh

jonny [76]

The answer is 30

2 * 15 = 30
5 * 6 = 30
30 is between 24 and 34

4 0

2 years ago

Two possible solutions of √11-2x=√x^2+4x+4 are –7 and 1. Which statement is true? A) Only x = –7 is an extraneous solution.

11111nata11111 [884]

Answer:

Option D)Neither solution is extraneous.

Step-by-step explanation:

we have

$\sqrt{11-2x}=\sqrt{x^{2}+4x+4}$

we know that

two possible solutions are x=-7 and x=1

<u><em>Verify each solution</em></u>

Substitute each value of x in the expression above and interpret the results

1) For x=-7

$\sqrt{11-2(-7)}=\sqrt{-7^{2}+4(-7)+4}$

$\sqrt{25}=\sqrt{25}$

$5=5$ ----> is true

therefore

x=-7 is not a an extraneous solution

2) For x=1

$\sqrt{11-2(1)}=\sqrt{1^{2}+4(1)+4}$

$\sqrt{9}=\sqrt{9}$

$3=3$ ----> is true

therefore

x=1 is not a an extraneous solution

therefore

Neither solution is extraneous

7 0

2 years ago

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