<h3>(a) The rock splashes down when h(t) = 0. Set h(t) = 0 and solve for t using quadratic formula.</h3>
<h3>0 = − 4.9t^2 + 334t + 255</h3>
<h3>t = -0.75, 68.92</h3>
<h3>(Throw away the negative answer, since time can't be negative.)</h3>
<h3>t = 68.92 sec</h3>
<h3>(b) The rock is at it's peak when the slope of it's trajectory is zero. This trajectory is also the tangent line, so finding when the slope of the tangent line is zero is the goal. To do this, take the derivative of h(t) and set h'(t) = 0.</h3>
<h3>h'(t) = -9.8t + 334</h3>
<h3>0 = -9.8t + 334</h3>
<h3>t = 34.08 sec</h3>
<h3>Use this time to find the height of the ball h(t), so h(34.08 sec).</h3>
<h3>h(t) = − 4.9(34.08)^2 + 334(34.08) + 255</h3>
<h3>h(t) = 5946.6m</h3>
<h3> And follow me </h3>
Step-by-step explanation:
the ratio is given above
Answer:
b =
Step-by-step explanation:
Given
A = × b × h
Multiply both sides by 2 to clear the fraction
2A = b × h ( divide both sides by h )
= b
Answer:
Step-by-step explanation:
We need to find the quantity demanded if the price of the shed is 1480$. Hence:
Sustract 1480 to both sides:
Multiply both sides by
We have a quadratic equation, we can solve it using the cuadratic formula or simply factoring it:
Now the solutions are given by:
Since we look for a coherent answer we take the positive solution
So the quantity demanded is