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Aleks04 [339]
3 years ago
6

A communications tower is supported by two wires, connected at the same point on the ground. One is attached to the tower at D a

nd the long-on at C. The angle AD makes with the ground is 30 ° and the angle between the two wires is 10 °. How much below the top of the tower is the shorter one attached?

Mathematics
1 answer:
viktelen [127]3 years ago
7 0

Answer:

10.99 m

Step-by-step explanation:

✍️What we are basically asked to solve here is to find the distance between C and D.

To find CD, find the length of BC, and BD. Their difference will give us CD.

Thus, BC - BD = CD.

✍️Finding BC using trigonometric ratio formula:

\theta = 30 + 10 = 40

Opposite side = BC = ??

Adjacent side = 42 m

Thus:

tan(\theta) = \frac{opposite}{adjacent}

Plug in the values

tan(40) = \frac{BC}{42}

Multiply both sides by 42

tan(40) \times 42 = \frac{BC}{42} \times 42

35.24 = BC

BC = 35.24 m

✍️Finding BD using trigonometric ratio formula:

\theta = 30

Opposite side = BD = ??

Adjacent side = 42 m

Thus:

tan(\theta) = \frac{opposite}{adjacent}

Plug in the values

tan(30) = \frac{BD}{42}

Multiply both sides by 42

tan(30) \times 42 = \frac{BD}{42} \times 42

24.25 = BD

BD = 24.25 m

✍️How much below the top of the tower is the shorter one attached:

Thus,

BC - BD = CD

35.24 m - 24.25 m = 10.99 m

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