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andrew11 [14]
3 years ago
5

A 90% confidence interval for the mean age, in weeks, at which a baby first crawls was reported to be (32, 46). The margin of er

ror for this confidence interval is
Mathematics
1 answer:
charle [14.2K]3 years ago
6 0

Answer:

The margin of error for this confidence interval is of 7.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

The margin of error is the subtraction between these bounds, divided by 2.

In this question:

The bounds are 32 and 46.

(46 - 32)/2 = 14/2 = 7

The margin of error for this confidence interval is of 7.

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4 years ago
Read 2 more answers
1/4k = 3 (-1/4k + 3)​
Arada [10]

Answer:

For the expression \frac{1}{4} k = 3 (-\frac{1}{4}k  +3)

k = 9 is the required solution.

Step-by-step explanation:

Here, the given expression is \frac{1}{4} k = 3 (-\frac{1}{4}k  +3)

Solving the above expression for k, we get:

\frac{1}{4} k = 3 (-\frac{1}{4}k  +3)  \implies  \frac{k}{4}  = (\frac{-3}{4}k) + 9

or, \frac{k}{4}  + (\frac{3}{4}k) =  9 \implies \frac{k + 3k}{4}   = 9

or, \frac{4k}{4}  = 9  \implies   k =9

or, k = 9

Hence for the expression \frac{1}{4} k = 3 (-\frac{1}{4}k  +3)

k = 9 is the required solution.

8 0
3 years ago
What is the interest rate if...<br> Principal = $1,250<br> Time = 4 years<br> Interest = $285.
alexandr402 [8]

Answer:

<h3>The answer is 5.7 %</h3>

Step-by-step explanation:

To find the rate given the principal , time and interest , we use the formula

r =  \frac{100I}{pt}  \\

where

p is the principal

t is the time

I is the interest

From the question

Principal = $1,250

Time = 4 years

Interest = $285

We have

r =  \frac{285 \times 100}{4 \times 1250}  =  \frac{28500}{5000}  =  \frac{285}{50}  \\  = 5.7

We have the final answer as

<h3>5.7 %</h3>

Hope this helps you

8 0
4 years ago
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