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Bess [88]
3 years ago
13

What is the mapping notation that will transform triangle ABC to triangle A'B'C'?

Mathematics
1 answer:
MissTica3 years ago
6 0

Answer:

I cant see it so can u do something so i can see it plz

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True or false, if y=7, then 5+27 < 20
barxatty [35]
False (take a look at the screenshot below)

5 0
3 years ago
1. Ethan writes 1/6 of a page in 1/12 of a minute. how much time does it take him to write a full page?
Nata [24]
I believe that the answer is 1/2 of a minute.
8 0
4 years ago
Read 2 more answers
Mr. Lopez wrote the equation 32 g + 8 g minus 10 g = 150 on the board. Four students explained how to solve for g.
11111nata11111 [884]

Answer:

Willhem

Step-by-step explanation:

The given equation is

Step 1 : Add 32g and 8g.

Step 2: Subtract 10 from 40.

Step 3: Divide both sides by 30, find the value of g.

The value of g is 5.

Therefore, Wilhem is correct.

7 0
3 years ago
Read 2 more answers
A rectangular garden is to be constructed using a rock wall as one side of the garden and wire fencing for the other three sides
givi [52]

Answer:

x  =  28 m

y  =  14  m

A(max)  =  392 m²

Step-by-step explanation:

Rectangular garden    A (r ) =  x * y

Let´s call x the side of the rectangle to be constructed with a rock wall, then only one x side of the rectangle will be fencing with wire.

the perimeter of the rectangle is  p  =  2*x  +  2*y    ( but in this particular case only one side x will be fencing with wire

56   =   x    +  2*y      56   -  2*y  =  x

A(r)   =  ( 56  -  2*y ) * y

A(y ) =  56*y  -  2*y²

Tacking derivatives on both sides of the equation we get:

A´(y )  =  56  - 4 * y        A´(y) = 0     56  -  4*y  =  0    4*y  =  56

y =  14 m

and x  =  56  - 2*y    =  56 - 28  = 28 m

Then dimensions of the garden:

x  =  28 m

y  =  14  m

A(max)  =  392 m²

How do we know that the area we found is a local maximum??

We find the second derivative

A´´(y)  = - 4     A´´(y)  <  0   then the function A(y) has a local maximum at y = 14 m

4 0
3 years ago
What is the possible arrangement for 22 students
lord [1]

\bf \stackrel{Permutations}{_nP_r=\cfrac{n!}{(n-r)!}}~\hspace{6em}\stackrel{\textit{22 units arranged in groups of 22}}{_{22}P_{22}=\cfrac{22!}{(22-22)!}} \implies _{22}P_{22}=\cfrac{22!}{0!} \\\\\\ _{22}P_{22}=\cfrac{22!}{1}\implies _{22}P_{22}=22!\implies _{22}P_{22}=1124000727777607680000

8 0
4 years ago
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