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N76 [4]
3 years ago
11

GETS BRAINLIST REAL EASY QUESTION!!! The table shows the ratio between the number of packets and the number of seeds of a certai

n plant contained in them: Number of packets Number of seeds 5 10 6 12 7 14 Which graph shows equivalent ratios? A graph is drawn. The horizontal axis and vertical axis values are 0 to 15 in increments of 1. The horizontal axis label is Number of Packets, and the vertical axis label is Number of Seeds. Points are plotted on the ordered pairs 1, 2 and 2, 4 and 3, 6. A graph is drawn. The horizontal axis and vertical axis values are 0 to 15 in increments of 1. The horizontal axis label is Number of Packets and the vertical axis label is Number of Seeds. Points are plotted on the ordered pairs 1, 2 and 2, 2 and 3, 2. A graph is drawn. The horizontal axis and vertical axis values are 0 to 15 in increments of 1. The horizontal axis label is Number of Packets, and the vertical axis label is Number of Seeds. Points are plotted on the ordered pairs 1, 1 and 2, 2 and 3, 3. A graph is drawn. The horizontal axis and vertical axis values are 0 to 15 in increments of 1. The horizontal axis label is Number of Packets, and the vertical axis label is Number of Seeds. Points are plotted on the ordered pairs 2, 1 and 4, 2 and 6, 3. Question 13(Multiple Choic
Mathematics
2 answers:
AleksAgata [21]3 years ago
7 0

Answer:

2

Step-by-step explanation:

Alecsey [184]3 years ago
5 0

Answer:

2

Step-by-step explanation:

i did the same one

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3 years ago
Read 2 more answers
Find the inverse of f(x)
FinnZ [79.3K]

Answer:

\huge\boxed{A.\  f^{-1}(x)=\dfrac{x-3}{5}}

Step-by-step explanation:

f(x)=5x+3\to y=5x+3\\\\\text{exchange}\ x\ \text{with}\ y\\\\5y+3=x\\\\\text{solve for}\ y\\\\5y+3=x\qquad|\text{subtract 3 from both sides}\\\\5y+3-3=x-3\\\\5y=x-3\qquad|\text{divide both sides by 5}\\\\\dfrac{5\!\!\!\!\diagup y}{5\!\!\!\!\diagup}=\dfrac{x-3}{5}\\\\y=\dfrac{x-3}{5}\to f^{-1}(x)=\dfrac{x-3}{5}

3 0
3 years ago
The intensity of light with wavelength λ traveling through a diffraction grating with N slits at an angle θ is given by I(θ) = N
Ymorist [56]

Answer:

0.007502795

Step-by-step explanation:

We have

N = 10,000

\bf d=10^{-4}

\bf \lambda = 632.8*10^{-9}

Replacing these values in the expression for k:

\bf k=\frac{\pi Ndsin\theta}{\lambda}=\frac{\pi10^4*10^{-4}sin\theta}{632.8*10^{-9}}=\frac{\pi 10^9sin\theta}{632.8}

So, the intensity is given by the function

\bf I(\theta)=\frac{N^2sin^2(k)}{k^2}=\frac{10^8sin^2(\frac{\pi 10^9sin\theta}{632.8})}{(\frac{\pi 10^9sin\theta}{632.8})^2}

The <em>total light intensity</em> is then

\bf \int_{-10^{-6}}^{10^{-6}} I(\theta)d\theta=\int_{-10^{-6}}^{10{-6}}\frac{10^8sin^2(\frac{\pi 10^9sin\theta}{632.8})}{(\frac{\pi 10^9sin\theta}{632.8})^2}d\theta

Since \bf I(\theta) is an <em>even function</em>

\bf \int_{-10^{-6}}^{10^{-6}} I(\theta)d\theta=2\int_{0}^{10^{-6}}I(\theta)d\theta

and we only have to divide the interval \bf [0,10^{-6}] in five equal sub-intervals \bf I_1,I_2,I_3,I_4,I_5 with midpoints \bf m_1,m_2,m_3,m_4,m_5

The sub-intervals and their midpoints are

\bf I_1=[0,\frac{10^{-6}}{5}]\;,m_1=10^{-5}\\I_2=[\frac{10^{-6}}{5},2\frac{10^{-6}}{5}]\;,m_2=3*10^{-5}\\I_3=[2\frac{10^{-6}}{5},3\frac{10^{-6}}{5}]\;,m_3=5*10^{-5}\\I_4=[3\frac{10^{-6}}{5},4\frac{10^{-6}}{5}]\;,m_4=7*10^{-5}\\I_5=[4\frac{10^{-6}}{5},10^{-6}]\;,m_5=9*10^{-5}

<em>By the midpoint rule</em>

\bf \int_{0}^{10^{-6}}I(\theta)d\theta\approx\frac{10^{-6}}{5}[I(m_1)+I(m_2)+...+I(m_5)]

computing the values of I:

\bf I(m_1)=I(10^{-5})=\frac{10^8sin^2(\frac{\pi 10^9sin(10^{-5})}{632.8})}{(\frac{\pi 10^9sin(10^{-5})}{632.8})^2}=13681.31478

\bf I(m_2)=I(3*10^{-5})=\frac{10^8sin^2(\frac{\pi 10^9sin(3*10^{-5})}{632.8})}{(\frac{\pi 10^9sin(3*10^{-5})}{632.8})^2}=4144.509447

Similarly with the help of a calculator or spreadsheet we find

\bf I(m_3)=3.09562973\\I(m_4)=716.7480066\\I(m_5)=211.3187228

and we have

\bf \int_{0}^{10^{-6}}I(\theta)d\theta\approx\frac{10^{-6}}{5}[I(m_1)+I(m_2)+...+I(m_5)]=\frac{10^{-6}}{5}(18756.98654)=0.003751395

Finally the the total light intensity

would be 2*0.003751395 = 0.007502795

8 0
3 years ago
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