Answer:
tan(2u)=[4sqrt(21)]/[17]
Step-by-step explanation:
Let u=arcsin(0.4)
tan(2u)=sin(2u)/cos(2u)
tan(2u)=[2sin(u)cos(u)]/[cos^2(u)-sin^2(u)]
If u=arcsin(0.4), then sin(u)=0.4
By the Pythagorean Identity, cos^2(u)+sin^2(u)=1, we have cos^2(u)=1-sin^2(u)=1-(0.4)^2=1-0.16=0.84.
This also implies cos(u)=sqrt(0.84) since cosine is positive.
Plug in values:
tan(2u)=[2(0.4)(sqrt(0.84)]/[0.84-0.16]
tan(2u)=[2(0.4)(sqrt(0.84)]/[0.68]
tan(2u)=[(0.4)(sqrt(0.84)]/[0.34]
tan(2u)=[(40)(sqrt(0.84)]/[34]
tan(2u)=[(20)(sqrt(0.84)]/[17]
Note:
0.84=0.04(21)
So the principal square root of 0.04 is 0.2
Sqrt(0.84)=0.2sqrt(21).
tan(2u)=[(20)(0.2)(sqrt(21)]/[17]
tan(2u)=[(20)(2)sqrt(21)]/[170]
tan(2u)=[(2)(2)sqrt(21)]/[17]
tan(2u)=[4sqrt(21)]/[17]
I think the answer would be 89
Answer:
148.12m²
Step-by-step explanation:
At first, lets find the area of rectangle.
length = 14m
breadth = 6m
Area of rectangle = length x breadth
= 14 x 6
= 84m²
Now, For the area of sector of the circle,
Given angle (a) = 34
radius = 14m
Area of the sector = a / 360 x pi x r²
= 34/360 x 3.14 x 14²
= 34 / 360 x 3.14 x 196
= 58.12m²
Now adding both areas,
84 + 58.12 = 142.12m²
X²-4x+(4/2)²-(4/2)²+13=0
x²-4x+4-4+13=0
-4 should be added
Mark brainliest please
