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larisa86 [58]
3 years ago
9

I need help please.

Mathematics
1 answer:
Travka [436]3 years ago
6 0

Answer:

9.8

Step-by-step explanation:

I just entered it into a calculator...

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If a bullentin board is 6 ft wide and 4 ft tall. what are the deminsions inside
SOVA2 [1]
If you are looking for the area the answer would be 24 ft. tall because 6*4 is 24
6 0
3 years ago
fladli sells televisions. He earns a fixed amount for each television and an additional $ 20 if the buyer gets an extended warra
ivanzaharov [21]

Answer: $80


Step-by-step explanation:

Given: The amount earned by Fadil on selling 14 televisions= $1400

Therefore, the amount he earned on selling 1 television=\frac{1400}{14}=\$100

Since, he sold televisions with extended warranty and he earns $20 additional for it.

Then, the fixed amount Fadil earns for each​ television=\$100-\$20=\$80

Hence, Fadil earns $80 as the fixed amount for each televison.

4 0
3 years ago
A trapezoid has an area of 60 square inches. The height of the trapezoid is 5 inches. What is the length of the longer base if t
Vinil7 [7]

Answer:

Step-by-step explanation:

Remark

Let the shorter base = x

Let the longer base = 3x

h = 5

Area = 60

Formula

Area = (b1 + b2)*h /2

Solution

60 = (x + 3x)*5 / 2                Multiply both sides by 2

2*60 = (x + 3x)*5                  Combine like terms

120 = 4x *5

120 = 20x                             Divide by 20

120/20 = x

x = 6

Therefore the two bases are

x = 6

3x = 18

5 0
2 years ago
Read 2 more answers
Consider the following equation. f(x, y) = y3/x, P(1, 2), u = 1 3 2i + 5 j (a) Find the gradient of f. ∇f(x, y) = Correct: Your
BaLLatris [955]

f(x,y)=\dfrac{y^3}x

a. The gradient is

\nabla f(x,y)=\dfrac{\partial f}{\partial x}\,\vec\imath+\dfrac{\partial f}{\partial y}\,\vec\jmath

\boxed{\nabla f(x,y)=-\dfrac{y^3}{x^2}\,\vec\imath+\dfrac{3y^2}x\,\vec\jmath}

b. The gradient at point P(1, 2) is

\boxed{\nabla f(1,2)=-8\,\vec\imath+12\,\vec\jmath}

c. The derivative of f at P in the direction of \vec u is

D_{\vec u}f(1,2)=\nabla f(1,2)\cdot\dfrac{\vec u}{\|\vec u\|}

It looks like

\vec u=\dfrac{13}2\,\vec\imath+5\,\vec\jmath

so that

\|\vec u\|=\sqrt{\left(\dfrac{13}2\right)^2+5^2}=\dfrac{\sqrt{269}}2

Then

D_{\vec u}f(1,2)=\dfrac{\left(-8\,\vec\imath+12\,\vec\jmath\right)\cdot\left(\frac{13}2\,\vec\imath+5\,\vec\jmath\right)}{\frac{\sqrt{269}}2}

\boxed{D_{\vec u}f(1,2)=\dfrac{16}{\sqrt{269}}}

7 0
3 years ago
El equipo mixto de fútbol tiene cuatro veces más niños que niñas. Decimos quela razón del número de niños
makvit [3.9K]

Answer:

4 a 1

Step-by-step explanation:

Se lee "4 a 1"

4 0
3 years ago
Read 2 more answers
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