The area of a rectangle is (length) times (width).
So you have to find a pair of numbers that multiply to produce 6 .
If you only stick to whole numbers, then I don't think there are three
different ones. You're going to need one pair that multiply to 6 and
are not both whole numbers.
After I explain how to solve problems, I hate to give answers. But with
all due respect, I have a feeling that I haven't nudged you enough yet
for you to use my explanation to find the answers on your own.
So here are some answers:
1 and 6
2 and 3
and sets of dimensions that are not both whole numbers, like
0.6 and 10
1.2 and 5
1.25 and 4.8
1.5 and 4
2.4 and 2.5
Answer:
X Y
-2 8
-1 7
0 6
1 5
2 4
3 3
Step-by-step explanation:
We have the equation: x+y=6
We want to get this in the form: y=mx+b (or in this case y=x+b)
To do this we need y to be positive and by itself
So we subtract y from both sides and divide by -1 (we divide by -1 because otherwise y would be negative and that does not fit our template of y=x+b)
Doing this we have
-x+6=y
From here we just plug in numbers -2 to 3 which I will assume you know how to do
X Y
-2 8
-1 7
0 6
1 5
2 4
3 3
Answer:
6:7
Step-by-step explanation:
divide both sides by 7...
Answer:
1.40476190476
Step-by-step explanation:
Solve for R:
R + 3 = -(1/2 + 6)
Put 1/2 + 6 over the common denominator 2. 1/2 + 6 = (2×6)/2 + 1/2:
R + 3 = -(2×6)/2 + 1/2
2×6 = 12:
R + 3 = -(12/2 + 1/2)
12/2 + 1/2 = (12 + 1)/2:
R + 3 = -(12 + 1)/2
12 + 1 = 13:
R + 3 = -13/2
Subtract 3 from both sides:
R + (3 - 3) = -13/2 - 3
3 - 3 = 0:
R = -13/2 - 3
Put -13/2 - 3 over the common denominator 2. -13/2 - 3 = (-13)/2 + (2 (-3))/2:
R = (-13)/2 - (3×2)/2
2 (-3) = -6:
R = (-6)/2 - 13/2
(-13)/2 - 6/2 = (-13 - 6)/2:
R = (-13 - 6)/2
-13 - 6 = -19:
Answer: R = (-19)/2
