2 years ago

PLEASE HELP!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

Mnenie [13.5K]2 years ago

7 0

A: 9
B: 5
C: 7

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Ernesto solves the equation below by first squaring both sides of the equation. \sqrt{\dfrac{1}{2}w+8}=-2 2 1 w+8 =−2square

algol [13]

Answer:

Step-by-step explanation:

Given the equation solved by Ernesto expressed as $\sqrt{\dfrac{1}{2}w+8}=-2$ , the extraneous solution obtained by Ernesto is shown below;

$\sqrt{\dfrac{1}{2}w+8}=-2\\\\square\ both \ sides \ of \ the \ equation\\(\sqrt{\dfrac{1}{2}w+8})^2=(-2)^2\\\\\dfrac{1}{2}w+8 = 4\\\\Subtract \ 8 \ from \ both \ sides\\\\\dfrac{1}{2}w+8 - 8= 4- 8\\\\\dfrac{1}{2}w= -4\\\\multiply \ both \ sides \ by \ 2\\\\\dfrac{1}{2}w*2= -4*2\\\\w = -8$