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Ann [662]
3 years ago
6

PLEASE HELP!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
7 0
A: 9
B: 5
C: 7


Codification biggest ig fh fh u I ygrrhji so so do to to do fh
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191.2=2.3L+65.5 helppppppppppppppppppppppppppp
svetlana [45]

Answer:

Step-by-step explanation:

191.2 = 2.3L +65.5

191.2 - 65.5 = 2.3L   {Subtract 65.5 from both sides}

125.7= 2.3L

L = 125.7/2.3

L = 54.65

3 0
3 years ago
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Which ordered pair is the solution to the system of linear equations y=5x+8 and -4x-1 ?
Margarita [4]
Hello : 
<span>
 y=5x+8
y= -4x-1 
5x+8 = -4x-1
9x =-9
x = -1 
y = 5(-1)+8 = 3 
</span><span>ordered pair is the solution to the system : ( -1 , 3)</span>
8 0
3 years ago
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Can one of y’all help me with this pls
Dafna11 [192]

Answer:

d. 42

Step-by-step explanation:

PEDMAS

We do brackets first, so:

4 + 4 = 8

Then multiplication,

5 x 8 = 40

Then addition

40 + 2 = 42

6 0
3 years ago
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Root 3 cosec140° - sec140°=4<br>prove that<br><br>​
Lorico [155]

Answer:

Step-by-step explanation:

We are to show that \sqrt{3} cosec140^{0} - sec140^{0} = 4\\

<u>Proof:</u>

From trigonometry identity;

cosec \theta = \frac{1}{sin\theta} \\sec\theta = \frac{1}{cos\theta}

\sqrt{3} cosec140^{0} - sec140^{0} \\= \frac{\sqrt{3} }{sin140} - \frac{1}{cos140} \\= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\

From trigonometry, 2sinAcosA = Sin2A

= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\\\=  \frac{\sqrt{3}cos140-sin140 }{sin280/2}\\=  \frac{4(\sqrt{3}/2cos140-1/2sin140) }{2sin280}\\\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{sin280}\\since sin420 = \sqrt{3}/2 \ and \ cos420 = 1/2  \\ then\\\frac{4(sin420cos140-cos420sin140) }{sin280}

Also note that sin(B-C) = sinBcosC - cosBsinC

sin420cos140 - cos420sin140 = sin(420-140)

The resulting equation becomes;

\frac{4(sin(420-140)) }{sin280}

= \frac{4sin280}{sin280}\\ = 4 \ Proved!

3 0
3 years ago
Consider the letters of the word STRIVE are written on individual cards are placed in a box.
Aleksandr [31]
Answer: 1/6

Explanation:
8 0
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