PLEASE HELP!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

Mnenie [13.5K]3 years ago

7 0

A: 9
B: 5
C: 7

Codification biggest ig fh fh u I ygrrhji so so do to to do fh

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191.2=2.3L+65.5 helppppppppppppppppppppppppppp

svetlana [45]

Answer:

Step-by-step explanation:

191.2 = 2.3L +65.5

191.2 - 65.5 = 2.3L {Subtract 65.5 from both sides}

125.7= 2.3L

L = 125.7/2.3

L = 54.65

3 0

3 years ago

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Which ordered pair is the solution to the system of linear equations y=5x+8 and -4x-1 ?

Margarita [4]

Hello :

y=5x+8
y= -4x-1
5x+8 = -4x-1
9x =-9
x = -1
y = 5(-1)+8 = 3
ordered pair is the solution to the system : ( -1 , 3)

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3 years ago

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Can one of y’all help me with this pls

Dafna11 [192]

Answer:

d. 42

Step-by-step explanation:

PEDMAS

We do brackets first, so:

4 + 4 = 8

Then multiplication,

5 x 8 = 40

Then addition

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3 years ago

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Root 3 cosec140° - sec140°=4 prove that

Lorico [155]

Answer:

Step-by-step explanation:

We are to show that $\sqrt{3} cosec140^{0} - sec140^{0} = 4\\$

Proof:

From trigonometry identity;

$cosec \theta = \frac{1}{sin\theta} \\sec\theta = \frac{1}{cos\theta}$

$\sqrt{3} cosec140^{0} - sec140^{0} \\= \frac{\sqrt{3} }{sin140} - \frac{1}{cos140} \\= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\$

From trigonometry, 2sinAcosA = Sin2A

$= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\\\= \frac{\sqrt{3}cos140-sin140 }{sin280/2}\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{2sin280}\\\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{sin280}\\since sin420 = \sqrt{3}/2 \ and \ cos420 = 1/2 \\ then\\\frac{4(sin420cos140-cos420sin140) }{sin280}$