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abruzzese [7]
3 years ago
14

Eighty-one million four hundred twelve thousand six hundred fifty​

Mathematics
1 answer:
Jobisdone [24]3 years ago
8 0

Answer:

81,412,650

Step-by-step explanation:

im not sure if this is what ur asking for??

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A Cepheid variable star is a star whose brightness alternately increases and decreases. For a certain star, the interval between
victus00 [196]

Answer:

a) \frac{dB}{dt} = \frac{5\pi}{4.2} \cdot \cos \left(2\pi\cdot \frac{t}{4.2} \right), b) \frac{dB}{dt}\approx 5.595

Step-by-step explanation:

a) The rate of change of the brightness of the Cepheid can be determined by deriving the function in time:

\frac{dB}{dt} = \left(\frac{2\pi}{4.2} \right)\cdot 0.25\cdot \cos (2\pi\cdot \frac{t}{4.2})

\frac{dB}{dt} = \frac{5\pi}{4.2} \cdot \cos \left(2\pi\cdot \frac{t}{4.2} \right)

b) The rate of increase after one day is:

\frac{dB}{dt} = \frac{5\pi}{4.2} \cdot \left(2\pi \cdot \frac{1}{4.2} \right)

\frac{dB}{dt}\approx 5.595

4 0
3 years ago
Please I Really Need Help.The coordinate plane below represents a city. Points A through F are schools in the city.
almond37 [142]

Answer:

Part A) The system of inequalities is

x\geq2  and  y\geq2

Part B) In the procedure

Part C) The schools that Natalie is allowed to attend are A,B and D

Step-by-step explanation:

Part A: Using the graph above, create a system of inequalities that only contain points C and F in the overlapping shaded regions

we have

Points C(2,2), F(3,4)

The system of inequalities could be

x\geq2 -----> inequality A

The solution of the inequality A is the shaded area at the right of the solid line x=2

y\geq2 -----> inequality B

The solution of the inequality B is the shaded area above of the solid line y=2

see the attached figure N 1

Part B: Explain how to verify that the points C and F are solutions to the system of inequalities created in Part A

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities

<em>Verify point C</em>

C(2,2)    

<em>Inequality A</em>

x\geq2 -----> 2\geq2 ----> is true

<em>Inequality B</em>

y\geq2 ------> 2\geq2 ----> is true

therefore

Point C is a solution of the system of inequalities

<em>Verify point D</em>

F(3,4)    

<em>Inequality A</em>

x\geq2 -----> 3\geq2 ----> is true

<em>Inequality B</em>

y\geq2 ------> 4\geq2 ----> is true

therefore

Point D is a solution of the system of inequalities

Part C: Natalie can only attend a school in her designated zone. Natalie's zone is defined by y < −2x + 2. Explain how you can identify the schools that Natalie is allowed to attend.

we have

y < -2x+2

The solution of the inequality is the shaded area below the dotted line y=-2x+2

The y-intercept of the dotted line is the point (0,2)

The x-intercept of the dotted line is the point (1,0)

To graph the inequality, plot the intercepts and shade the area below the dotted line

see the attached figure N 2

therefore

The schools that Natalie is allowed to attend are A,B and D

3 0
2 years ago
Plz help!!! due tonight I need help!!!!​
Pachacha [2.7K]

Answer:

14400

Step-by-step explanation: i culd be wrong tho

3 0
2 years ago
Read 2 more answers
The table below shows the surface area y in square inches, of a shrinking puddle in x hours
Kruka [31]
Part A
Correlation coefficient: -.99
This tells us that as time goes on (value of x increases) the area of the puddle goes down (value of y decreases)

Part B
y₂ - y₁
-------   = slope
x₂ - x₁
9 - 15
--------
5 - 8
-6/-3 = 2
So the slope equals -2, regardless of the fact that we got 2 as an answer there, we know that it is a negative slope 

Part C
The data represents causation because an increase in the value of x results in a decrease in the value of y, this shows an example of direct causation between x and y.
8 0
3 years ago
Read 2 more answers
Assume that k and V0 are constant and are, respectively, 0.02, and 7. The parameter CA varies from an initial value CA0 = 100 to
julia-pushkina [17]

Answer:

V = 929.7

Step-by-step explanation:

Given the equation:

\frac{dCA}{dV} = \frac{-kCA}{V0}

The integral of the above equation is:

\int\limits {\frac{dCA}{dV} } = \int\limits{\frac{-kCA}{V0} }

Re-organizing the integrals:

\int\limits  {\frac{dCA}{CA} } = \int\limits {\frac{-kdV}{V0} }

Integrating:

ln(CA) - ln(CA0) = \frac{-kV}{V0}

Inputting the initial conditions of CA and the values of k and V0:

ln(7) - ln(100) = \frac{-0.02V}{7}

1.946 - 4.605 = -0.00286V

-2.659 = -0.00286V

=> V = \frac{2.659}{0.00286}

V = 929.720

Approximating to one decimal place,

V = 929.7

7 0
2 years ago
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