All categories

3 years ago

PLZ HELP ME!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

jekas [21]3 years ago

5 0

Answer:

x^3 - 4x^2 - 11x - 6

Step-by-step explanation:

Hope I helped :)!!

You might be interested in

Please help me guys

Marianna [84]

If you multiply $60 by 0.15 you'll get 9 which is the taxes of the meal. Since he leaves the same percentage of tip, now we add 9+9 and get $18..
60+18=78

6 0

3 years ago

PLEASE HELP ILL MARK BRAINLIEST AND GIVE 5 STATS AND LIKE IT PLEASE

Dahasolnce [82]

Answer:

36÷3÷2÷3=2

Step-by-step explanation:

8 0

2 years ago

What is 3k-14=3(k-5)+1 ?

stealth61 [152]

Answer:

True

Step-by-step explanation:

3k-14=3(k-5)+1

3k-14=3k-15+1

3k-3k=14-15+1

0=14-15+1

-14=-15+1

-14=-14

8 0

3 years ago

The prices of commodities X,Y,Z are respectively x, y, z, rupees per unit. Mr. A purchases 4 units of Z and sells 3 units of X a

liubo4ka [24]

Answer:

$(x,y,z)=(1477, 1464, 1437)$

Step-by-step explanation:

Consider the selling of the units positive earning and the purchasing of the units negative earning.

Mr. A purchases 4 units of Z and sells 3 units of X and 5 units of Y
Mr.A earns Rs6000

So, the equation would be

$3x + 5y - 4z = 6000$

Mr. B purchases 3 units of Y and sells 2 units of X and 1 units of Z
Mr B neither lose nor gain meaning he has made 0₹

hence,

$2x - 3y + z = 0$

Mr. C purchases 1 units of X and sells 4 units of Y and 6 units of Z
Mr.C earns 13000₹

therefore,

$- x + 4y + 6z = 13000$

Thus our system of equations is

$\begin{cases}3x + 5y - 4z = 6000\\2x - 3y + z = 0\\ - x + 4y + 6z = 13000\end{cases}$

<u>Solving </u><u>the </u><u>system </u><u>of </u><u>equations</u><u>:</u>

we will consider elimination method to solve the system of equations. To do so ,separate the equation in two parts which yields:

$\begin{cases}3x + 5y - 4z = 6000\\2x - 3y + z = 0\end{cases}\\\begin{cases}2x - 3y + z = 0\\ - x + 4y + 6z = 13000\end{cases}$

Now solve the equation accordingly:

$\implies\begin{cases}11x-7y=6000\\-13x+22y=13000\end{cases}$

Solving the equation for x and y yields:

$\implies\begin{cases}x= \dfrac{223000}{151}\\\\y= \dfrac{221000}{151}\end{cases}$

plug in the value of x and y into 2x - 3y + z = 0 and simplify to get z. hence,

$\implies z= \dfrac{217000}{151}$

Therefore,the prices of commodities X,Y,Z are respectively approximately 1477, 1464, 1437

6 0

3 years ago

Need help with an exam question

stealth61 [152]

Take a pic with phone and it will give u answer

4 0

3 years ago