Ask question

Ask question

All categories

4 years ago

6

Find the missing number. 72 ÷ = 9

2 answers:

yawa3891 [41]4 years ago

8 0

Answer:

8

Step-by-step explanation:

iren [92.7K]4 years ago

4 0

Answer:

8

Step-by-step explanation:

9 x 8=72

You might be interested in

Round 10,982 to the nearest hundred

zvonat [6]

Answer:

4568

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Please help! - Kim needs to place 32 mystery books and 56 biography books on library shelves. She is to place the maximum number

Oksi-84 [34.3K]

A. 8 books on each shelf
B. 4 shelves for mystery, 7 shelves for biography

3 0

3 years ago

Read 2 more answers

Which number rounds to 15,700,000 when rounded to the nearest hundred thousand?. A) 15,000,000. B) 15,579,999. C) 15,649,999. D)

Artyom0805 [142]

<span>The correct answer is option D. i.e. 15,659,999. Now, this number is closest to the given number i.e. 15,700,000. Becuase when 659 is rounded to the nearest number of hiher value then its value will be 700. Thus,15,659, 999 rounds to 15,700,000 when rounded to the nearest hundred thousand.</span>

6 0

4 years ago

Need math help please!!

dem82 [27]

Answer:

my best guess is A

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

In Exercises 45–48, let f(x) = (x - 2)2 + 1. Match the<br> function with its graph

MA_775_DIABLO [31]

Answer:

45) The function corresponds to graph A

46) The function corresponds to graph C

47) The function corresponds to graph B

48) The function corresponds to graph D

Step-by-step explanation:

We know that the function f(x) is:

$f(x)=(x-2)^{2}+1$

45)

The function g(x) is given by:

$g(x)=f(x-1)$

using f(x) we can find f(x-1)

$g(x)=((x-1)-2)^{2}+1=(x-3)^{2}+1$

If we take the derivative and equal to zero we will find the minimum value of the parabolla (x,y) and then find the correct graph.

$g(x)'=2(x-3)$

$2(x-3)=0$

$x=3$

Puting it on g(x) we will get y value.

$y=g(3)=(3-3)^{2}+1$

$y=g(3)=1$

<u>Then, the minimum point of this function is (3,1) and it corresponds to (A)</u>

46)

Let's use the same method here.

$g(x)=f(x+2)$

$g(x)=((x+2)-2)^{2}+1$

$g(x)=(x)^{2}+1$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2x$

$0=2x$

$x=0$

Evaluatinf g(x) at this value of x we have:

$g(0)=(x)^{2}+1$

$g(0)=1$

<u>Then, the minimum point of this function is (0,1) and it corresponds to (C)</u>

47)

Let's use the same method here.

$g(x)=f(x)+2$

$g(x)=(x-2)^{2}+1+2$

$g(x)=(x-2)^{2}+3$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}+3$

$g(2)=3$

<u>Then, the minimum point of this function is (2,3) and it corresponds to (B)</u>

48)

Let's use the same method here.

$g(x)=f(x)-3$

$g(x)=(x-2)^{2}+1-3$

$g(x)=(x-2)^{2}-2$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}-2$

$g(2)=-2$

<u>Then, the minimum point of this function is (2,-2) and it corresponds to (D)</u>

<u />

I hope it helps you!

<u />

8 0

3 years ago