Question

Find the equation perpendicular to the line y=−3x+5 that passes through point (2, 6).

Answer 1

Hey there! :)

Perpendicular to y = -3x + 5 ; passes through (2, 6).

Our slope is -3. We know this because it is in the "m" position from slope-intercept form. However, since our equation we're looking for is perpendicular to our given one, we must find the negative reciprocal of -3.

A negative reciprocal is simply a number that is flipped and either given a negative or gets a negative removed.

So the negative reciprocal of -3 is 1/3. This means that our new slope is 1/3.

Now, using point-slope form ( y-y₁=m(x-x₁) ), our new slope (1/3) & (2, 6) , let's find our new equation!

y-y₁=m(x-x₁) y - (6) = 1/3(x - 2)

Simplify.

y - 6 = 1/3x - 2/3

~Hope I helped!~

Answer 2

Attached the solution and work.