Apply the Pyth. Theorem:
c^2 = 3^2 + 7^2, or c^2 = 9 + 49 = 58. Thus, c = sqrt(58).
Answer:
176.625 sq.ft, 4.8 sq.ft
Step-by-step explanation:
Area of circle=πr^2 or πd^2/4
11. Given,
d=15 ft
Now,
Area=πd^2/4
3.14*15^2/4
176.625 ft^2
Therefore, the area approximation is 176.6 sq.ft
12.
Given,
d=3.5 ft
Now,
Area= πd^2/8
3.14*3.5^2/8
4.8 sq.ft
I got the answer by dividing the area of circle by 2 as semicircle is half of circle.
Answer:
Between 15.95 ounces and 16.15 ounces.
Step-by-step explanation:
We have the following value m, being the mean, sd, being the standard deviation and n, the sample size:
m = 16.05
sd = 0.1005
n = 4
We apply the formula of this case, which would be:
m + - 2 * sd / (n ^ 1/2)
In this way we create a range, replacing we have:
16.05 + 2 * 0.1005 / (4 ^ 1/2) = 16.1505
16.05 - 2 * 0.1005 / (4 ^ 1/2) = 15.9495
Which means that 95% of all samples are between 15.95 ounces and 16.15 ounces.
